Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 21 May 2013, 12:42

# inscribed coordinate geometry (m06q32)

Author Message
Intern
Joined: 16 Jul 2012
Posts: 2
Followers: 0

Kudos [?]: 0 [0], given: 3

Re: inscribed coordinate geometry (m06q32) [#permalink]  26 Oct 2012, 22:17
Area of sector BOC - area of triangle BOC

pi*sq(sqrt(6))*[90/360] - [1/2]*sqrt(6)*sqrt(6)

= [3pi/2] - 3
Attachments

Untitled.png [ 22.1 KiB | Viewed 226 times ]

Intern
Status: Researching; Essays
Joined: 18 Jan 2012
Posts: 5
Followers: 1

Kudos [?]: 7 [1] , given: 2

Re: inscribed coordinate geometry (m06q32) [#permalink]  28 Oct 2012, 04:51
1
KUDOS
There is a slightly more convoluted approach.
Attachments

Area.png [ 48.88 KiB | Viewed 202 times ]

Intern
Status: Active
Joined: 30 Jun 2012
Posts: 37
Location: India
Followers: 4

Kudos [?]: 44 [0], given: 36

Re: inscribed coordinate geometry (m06q32) [#permalink]  28 Oct 2012, 08:32
Great problem Bunuel! This one was simpler - Thanks to your MATH NOTE on polygons.

1. As circle is circumscribed to the square - Area of circle = \frac{Pi}{2}*(Area of square). So this means we need to know area of sqaure first.
2. Area of sqaure = \frac{(diagonal)^2}{2} and diagonal (in this case) = 2 * radius i.e 2\sqrt{6}.Therefore, Area of square = 12 and Area of circle (using point 1) = \frac{Pi}{2}*12.
3. Now, area of all 4 sectors = area of circle - area of sqaure and area of 1 sector (say CD) = \frac{1}{4}*(AREA of 4 sectors)
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post.

Re: inscribed coordinate geometry (m06q32)   [#permalink] 28 Oct 2012, 08:32
Similar topics Replies Last post
Similar
Topics:
Coordinate geometry 3 08 Nov 2005, 22:15
Coordinate Geometry 2 04 May 2008, 14:52
Coordinate geometry 1 19 Jun 2008, 04:58
7 inscribed coordinate geometry (m06q32) 22 12 Nov 2007, 11:56
1 Coordinate Geometry 3 25 May 2011, 12:09
Display posts from previous: Sort by

# inscribed coordinate geometry (m06q32)

 Go to page   Previous    1   2   [ 23 posts ]

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.