Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 28 Jun 2016, 06:58

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Interesting PS question: combination and arithmatic

Author Message
Manager
Joined: 14 Aug 2009
Posts: 123
Followers: 2

Kudos [?]: 98 [0], given: 13

Interesting PS question: combination and arithmatic [#permalink]

Show Tags

24 Aug 2009, 06:45
00:00

Difficulty:

(N/A)

Question Stats:

100% (02:12) correct 0% (00:00) wrong based on 1 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For a certain race, 3 teams were allowed to enter 3 members each. A team earned 6 – n points whenever one of its members finished in nth place, where 1 ≤ n ≤ 5. There were no ties, disqualifications, or withdrawals. If no team earned more than 6 points, what is the least possible score a team could have earned?

A. 0
B. 1
C. 2
D. 3
E. 4
_________________

Kudos me if my reply helps!

Intern
Joined: 24 Jun 2009
Posts: 42
Followers: 0

Kudos [?]: 3 [1] , given: 1

Re: Interesting PS question: combination and arithmatic [#permalink]

Show Tags

24 Aug 2009, 07:38
1
KUDOS
flyingbunny wrote:
For a certain race, 3 teams were allowed to enter 3 members each. A team earned 6 – n points whenever one of its members finished in nth place, where 1 ≤ n ≤ 5. There were no ties, disqualifications, or withdrawals. If no team earned more than 6 points, what is the least possible score a team could have earned?

A. 0
B. 1
C. 2
D. 3
E. 4

Is it 3. i.e D
since max possible points 15 [(6-1)+ (6-2)+(6-3)+(6-4)+(6-5)] and note that only 5 positions in the race get a point. so position number 6, 7, 8 and 9 are of '0' points.
No team gets more than 6 points. so assume two teams got 6 points sets could be (5,1,0), (2,4,0) and (3,0,0) thus least possible score is 3
Director
Joined: 01 Apr 2008
Posts: 898
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 24

Kudos [?]: 502 [0], given: 18

Re: Interesting PS question: combination and arithmatic [#permalink]

Show Tags

24 Aug 2009, 08:02
Exactly, idea is to divide 1,2,3,4,5,0,0,0,0 into three groups such that that two groups have the maximum value which is <=6. Whatever is left is the minimum number of points that the third team shall get.
Manager
Joined: 18 Jul 2009
Posts: 169
Location: India
Schools: South Asian B-schools
Followers: 2

Kudos [?]: 85 [0], given: 37

Re: Interesting PS question: combination and arithmatic [#permalink]

Show Tags

24 Aug 2009, 08:09
OA D = 3

3 teams (T1, T2, T3) with 3 members each with following point system

1 st place = 5 points
2nd place = 4 points
3 rd place = 3 points
4 th place = 2 points
5 th place = 1 point
6th place onwards (ie 6th/7th/8th/9th) = 0 points

Now only refer point table for furthur calculations
( keep in mind that there can be 4 positions with 0 score)

Lets say...T1 has team member with 1st position thus possible scores are ( 510 / 500) with these possible combinations T2 possible combinations are ( 420 / 410 / 400)...(we can see all possibilities in the image attached for clarity only not to be done in exam).....we can understand that T1 & T2 with max scores will lead T3 with Least score hence only possible combination between them is T1 (5,1,0) T2 (4,2,0) => T3 ( 3,0,0)...Hence OA D = 3
Attachments

SCORE.GIF [ 6.68 KiB | Viewed 768 times ]

_________________

Bhushan S.
If you like my post....Consider it for Kudos

Re: Interesting PS question: combination and arithmatic   [#permalink] 24 Aug 2009, 08:09
Display posts from previous: Sort by