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# Is 0.n68<1/n? 1). n<5 2). 0.n68<1/n^2

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Senior Manager
Joined: 22 Nov 2005
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Is 0.n68<1/n? 1). n<5 2). 0.n68<1/n^2 [#permalink]  27 May 2006, 13:32
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Is 0.n68<1/n?
1). n<5
2). 0.n68<1/n^2
SVP
Joined: 01 May 2006
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I go on (B)

(1) n<5
n=1 or 2 or 3 or 4

for n= 1 or 2, the inequality is verified
for n=3 or above, the inequality is not verified
Not Sufficient

(2) 0,n68 < 1/n^2
Only n=1 works with it.

As we know n, so we can conclude 0,n68 < 1/n
Manager
Joined: 25 Apr 2006
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I'll go with E.

if n=0 the expression goes to infinity which is indeterminate.
Director
Joined: 10 Oct 2005
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I will go with B...n wont be zero. Typically GMAT exam will make that assumption...
Senior Manager
Joined: 08 Jun 2004
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yessuresh wrote:
I'll go with E.

if n=0 the expression goes to infinity which is indeterminate.

Hey dude, n cab bot be equal to 0, we can not divide any number by zero.
Manager
Joined: 31 Mar 2006
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The ques is asking Is .n68<1/n and not for what value of n.

It should be E.
Please correct me if i am wrong.
Manager
Joined: 11 Oct 2005
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amansingla4 wrote:
The ques is asking Is .n68<1/n and not for what value of n.

It should be E.
Please correct me if i am wrong.

I go with B. The statement only works with B and the question is asking if we have enough information to answer the question. Since with B we know that n=1 we plug that back into the question and find that 0.168 is indeed less than 1 and sufficient to answer the question. Hope this helps.
Intern
Joined: 04 May 2006
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I go with E.
Putting 1 & 4 in eqn 1 gives two different answers.
similarly, putting 1 & 4 in eqn 2 gives 2 diff answeres.
so It can't be answers even combining them together.
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Manager
Joined: 10 May 2006
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I go with E as well.

Both 1 and 4 work as n.

If n= 1, then the answer is Yes
If n = 4, the answer is no

SVP
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yessuresh wrote:
I'll go with E.

if n=0 the expression goes to infinity which is indeterminate.

For this question we should infer that n is a number from 1 to 9. The fact that 1/n is included in the stem has precluded the possibility of n=0. For GMAT remember if something appears in the denominator, it is non zero. However, if you see something like n*0.n68<1, you cannot devide both sides by n while assuming n is non-zero.
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Manager
Joined: 05 Jun 2006
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In fact, in the decimal represtentation of a number, n is a positive integer from 0 to 9.

If the second statement is true, n=1. For n=0 the expression is nonsense, because you cannot divide by 0.

Note that in evaluating the sufficiency of the first statement you have to consider the case n=0, because n<5 does not exclude this possibility. Whereas, in evaluating the sufficiency of the second statement, you haven't to consider n=0, because for n=0 the hypothesis you should assume to be true would not be verified.
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# Is 0.n68<1/n? 1). n<5 2). 0.n68<1/n^2

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