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Is 1/ ( a-b ) < b-a? 1. a<b 2.1<|a-b

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Manager
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 [#permalink] New post 13 Apr 2006, 08:50
chiragr wrote:
so a-b is negative and b-a is positive
=> 1/a-b is negative and b-a is positive


:!: :!: H E L P :!: :!:

Could anybody release me please :twisted:

Am I the only one who thinks that it's a major difference if it's
1/a-b OR
1/(a-b)


I'm sorry, but the question tells us that it's
1/a-b = (1/a) - b
AND NOT
1 / (a-b)
.

The problem is, that this - besides the math - leads to another answer,
which is E.
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 [#permalink] New post 13 Apr 2006, 12:30
Here's my solution. I only have 1 minute so please let me know if the logic is not correct.

We want to know if 1/(a-b)<b-a

In other words if (b-a)-1/(a-b)>0
or if (-(a-b)^2-1)/(a-b)>0

We can see that the numerator is definitely negative. So the only thing we need to know is if a-b>0

1) answers it. Therefore sufficient.
2) a-b could be negative or positive. Thus insufficent.

Therefore the answer is A.
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 [#permalink] New post 13 Apr 2006, 12:40
HongHu wrote:
I only have 1 minute so please let me know if the logic is not correct.


Well done for a minute and the logic IS correct :-D
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 [#permalink] New post 13 Apr 2006, 12:48
I got A.

Statement 2 is not sufficient.

I tried a=4, b=1 which did not satisfy both equations.
Next, I tried a=-2, b=2, which satisfied both equations.
  [#permalink] 13 Apr 2006, 12:48
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