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Is 1/x < 1/y for integers x,y ? (1) x^2 + y^2 = 25 (2) xy [#permalink]
 04 Nov 2005, 19:05
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Is 1/x < 1/y for integers x,y ?
(1) x^2 + y^2 = 25
(2) xy = 12
Last edited by duttsit on 04 Nov 2005, 19:27, edited 1 time in total.
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Re: DS: abralgebra [#permalink]
04 Nov 2005, 19:23
duttsit wrote: Is 1/x < 1/y for integers x,y ?
(1) x^2 - y^2 = 25
(2) xy = 12
Is 1/x < 1/y for integers x,y?
1/x - 1/y < 0? --> (y-x)/xy < 0?
(1) x^2 - y^2 = 25 --> (x+y)(x-y) = 25. Insufficient.
(2) xy = 12. So for (y-x)/xy < 0, (y-x) has to be negative. Insufficient.
Together, still not sufficient. My answer is E
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Re: DS: abralgebra [#permalink]
04 Nov 2005, 19:28
TeHCM wrote: duttsit wrote: Is 1/x < 1/y for integers x,y ?
(1) x^2 - y^2 = 25
(2) xy = 12 Is 1/x < 1/y for integers x,y? 1/x - 1/y < 0? --> (y-x)/xy < 0? (1) x^2 - y^2 = 25 --> (x+y)(x-y) = 25. Insufficient. (2) xy = 12. So for (y-x)/xy < 0, (y-x) has to be negative. Insufficient. Together, still not sufficient. My answer is E TeHCM, please look at question again. there was a typo in statement (1). sorry about that.
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Re: DS: abralgebra [#permalink]
04 Nov 2005, 19:42
duttsit wrote: Is 1/x < 1/y for integers x,y ?
(1) x^2 + y^2 = 25
(2) xy = 12
Is 1/x < 1/y?
Implies that x has to be bigger than y for the equation to hold.
(1) x or y could be +- 3 or +-4. Insufficient.
(2) xy = 12, which implies that both integers could either be negative or positive. But it still doesn't tell us if x or y is bigger. Insufficient.
Both together. Stil not sufficient. My answer is still E.
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Current Student
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folks...i am on a bad roll here totally out of stamina
though ....I am going with E
1/x < 1/y ?
well...DONT cross MULTIPLY as we dont know which side the equality sign points to
(1) clearly Insuff....
(2) xy=12, well then x=12/y
1/x=y/12
questions is asking is y/12<1/y Y is an integer...so eliminate fraction...
now we dont know the sign of Y is it positive or negative...so E...
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Director
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I am also with E ..
A ) take X =3 , Y = 4
1/X<1/Y No but if X=4 and Y =3 then 1/X< 1/Y so InSuff
B ) take X = 2 , Y =6
1/X<1/Y No but if X=6 and Y = 2 then 1/X<1/Y Yes so InSuff
both together also gives Yes and No with (3,4) and (4,3) so both together are also not sufficient .....Hence answer E
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OA is E. Good work all the way.
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Director
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Darn why didn't I see this thread earlier - good question Duttsit.
_________________
"Wow! Brazil is big." —George W. Bush, after being shown a map of Brazil by Brazilian president Luiz Inacio Lula da Silva, Brasilia, Brazil, Nov. 6, 2005
http://www.nytimes.com/2005/11/21/inter ... prexy.html
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