Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\) --> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\) --> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

Answer: C.

HI Bunuel..

in S1: \(x=y\) , you considered 2 cases , \(y<0\) and \(y>0\) but why you did not consider \(x=y=0\)? _________________

Working without expecting fruit helps in mastering the art of doing fault-free action !

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\) --> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

Answer: C.

HI Bunuel..

in S1: \(x=y\) , you considered 2 cases , \(y<0\) and \(y>0\) but why you did not consider \(x=y=0\)?

x is in denominator it can not be zero. _________________

S1 + S2 -> 1/Y >0 -> Y^5 < Y^5 + 1/Y -> C is the answer

You can not cross multiply as you don't know the signs of x^5 and y (y^6+1 is positive). For example if x=1 and y=-1 then: 1/x^5=1>-1/2=y/(y^6+1) but x^5=1>-2=(y^6+1)/y (> not < as you wrote).

Never multiply or divide inequality by a variable (or by an expression with variable) unless you are sure of its sign since you do not know whether you must flip the sign of the inequality. _________________

S1 + S2 -> 1/Y >0 -> Y^5 < Y^5 + 1/Y -> C is the answer

You can not cross multiply as you don't know the signs of x^5 and y (y^6+1 is positive). For example if x=1 and y=-1 then: 1/x^5=1>-1/2=y/(y^6+1) but x^5=1>-2=(y^6+1)/y (> not < as you wrote).

Never multiply or divide inequality by a variable (or by an expression with variable) unless you are sure of its sign since you do not know whether you must flip the sign of the inequality.

Got you. Thanks bro _________________

"Life is like a box of chocolates, you never know what you'r gonna get"

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\)--> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

Answer: C.

In A, are you asking us to consider y being negative or did you derive it. Consideration would make sense to me, but I'm just trying to learn for the future. Sorry to be asking all this simple questions, but I just need to know. Thank you Bunuel!

Mari _________________

Thank you for your kudoses Everyone!!!

"It always seems impossible until its done." -Nelson Mandela

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\)--> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

Answer: C.

In A, are you asking us to consider y being negative or did you derive it. Consideration would make sense to me, but I'm just trying to learn for the future. Sorry to be asking all this simple questions, but I just need to know. Thank you Bunuel!

Mari

We should determine whether \(\frac{1}{y^5}>\frac{y}{y^6+1}\) is true. You can do this algebraically or with number plugging (for example test y=1 to get YES and then y=-1 to get NO).

As for algebraic approach: we should somehow simplify \(\frac{1}{y^5}>\frac{y}{y^6+1}\) (as it looks kind of ugly) to get the answer. For this we consider two cases: \(y<0\) and \(y>0\) (y=0 is not possible as y is in denominator and we know that division by zero is undefined). As we proceed, we get NO answer for an assumption \(y<0\) and we get YES answer for an assumption \(y>0\).

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\)--> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

Answer: C.

In A, are you asking us to consider y being negative or did you derive it. Consideration would make sense to me, but I'm just trying to learn for the future. Sorry to be asking all this simple questions, but I just need to know. Thank you Bunuel!

Mari

We should determine whether \(\frac{1}{y^5}>\frac{y}{y^6+1}\) is true. You can do this algebraically or with number plugging (for example test y=1 to get YES and then y=-1 to get NO).

As for algebraic approach: we should somehow simplify \(\frac{1}{y^5}>\frac{y}{y^6+1}\) (as it looks kind of ugly) to get the answer. For this we consider two cases: \(y<0\) and \(y>0\) (y=0 is not possible as y is in denominator and we know that division by zero is undefined). As we proceed, we get NO answer for an assumption \(y<0\) and we get YES answer for an assumption \(y>0\).

Hope it's clear.

Yes! It is very clear now, thanks! I was just wondering whether you considered y -ve... now I understand. Thank you so much for your patience! _________________

Thank you for your kudoses Everyone!!!

"It always seems impossible until its done." -Nelson Mandela

If it would have been Is 1/x^5 > 1/(y^6+1) ? Then can I rephrase it as

Is x^5 < y^6+1 ? irrespective of the signs. Am I correct?

Bunuel wrote:

Is 1/x^5 > y/(y^6+1)?

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\) --> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

If it would have been Is 1/x^5 > 1/(y^6+1) ? Then can I rephrase it as

Is x^5 < y^6+1 ? irrespective of the signs. Am I correct?

Bunuel wrote:

Is 1/x^5 > y/(y^6+1)?

(1) x=y --> is \(\frac{1}{y^5}>\frac{y}{y^6+1}\)? Two cases:

A. \(y<0\) --> cross multiply and as for negative \(y\): \(y^5<0\) and \(y^6+1>0\) flip the sign (because of negative \(y^5\)). The question becomes: is \(y^6+1<y^6\)? --> is \(1<0\)? In this case the answer would be NO.

B. \(y>0\) --> cross multiply and as for positive \(y\) both \(y^5\) and \(y^6+1\) are positive remain the sign. The question becomes: is \(y^6+1>y^6\)? --> is \(1>0\)? In this case the answer would be YES.

(2) y>0. Clearly insufficient as no info about \(x\).

(1)+(2) As from (2) \(y>0\) then we have case B and the answer is YES. Sufficient.

You can not cross multiply as you don't know the sign of x^5.

Never multiply or divide inequality by a variable (or by an expression with variable) unless you are sure of its sign since you do not know whether you must flip the sign of the inequality. _________________

Re: Is 1/x^5 > y/(y^6+1)? [#permalink]
07 Feb 2014, 09:04

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: Is 1/x^5 > y/(y^6+1)? [#permalink]
07 Feb 2014, 18:55

Is 1/x^5 > y/(y^6+1)? or is x^5 < (y^6+1)/y? (taking reciprocals changes the sign of inequality)

(1) x = y -> is x^ 5 < (x^6 + 1)/x or is x^5 < x^5 + 1/x? put x = 1, yes. Put x = -1, No. (2) y > 0 -> no info on x. NOT sufficient

Combining, x = y > 0. For +ve values, x^5 always less than x^5 +1/x. example: integer values. Put x = 2; Yes. non-integer values: put 1/2. 1/x on the RHS will make it RHS a bigger number.

C

gmatclubot

Re: Is 1/x^5 > y/(y^6+1)?
[#permalink]
07 Feb 2014, 18:55

Hey, everyone. After a hectic orientation and a weeklong course, Managing Groups and Teams, I have finally settled into the core curriculum for Fall 1, and have thus found...

MBA Acceptance Rate by Country Most top American business schools brag about how internationally diverse they are. Although American business schools try to make sure they have students from...

For the past couple of weeks I’ve been winding down my affairs in New York by working on consulting projects, trying every exotic sandwich there is and then intensely...