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Question Stats:
48% (01:46) correct
51% (01:13) wrong based on 1 sessions
Is 1/x-y < y - x ? (1) y is positive. (2) x is negative.
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Re: Inequality...involving reciprocals [#permalink]
 15 Jan 2012, 06:35
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Re: Is 1/x-y<y-x? (1) y is positive (2) x is negative [#permalink]
15 Jan 2012, 10:07
Is 1/(x-y) < y - x ?
1
______ - (y-x) < 0
(x-y)
(1) y is positive.
(2) x is negative.
From 1 and 2 -
(x-y) is always negative.
(y-x) will be positive
-(y-x) will be negative
Adding 2 negatives = -ve
If it were 1/(x-y) < x - y then answer would have been E
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Re: Is 1/x-y<y-x? (1) y is positive (2) x is negative [#permalink]
09 May 2012, 17:18
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Slightly different approach, I hope everyone can see the attached images with solutions. Dabral Apoorva81 wrote: Is 1/x-y < y - x ?
(1) y is positive.
(2) x is negative.
can you please provide detailed explanation..??
Attachments
image1.png [ 57.59 KiB | Viewed 919 times ]
image2.png [ 44.46 KiB | Viewed 919 times ]
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I'm having trouble understanding how to solve this problem. Can someone please help me?
1/(x-y) < y-x?
(1) y is positive
(2) x is negative
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In order to separate your x's and y's from each other, you need to know which term is larger. This is because you need to know whether x-y or y-x is negative (one of them will be, unless they are equal). Taking both statements together, you know that the two variables are not equal, and you can manipulate the inequality, keeping in mind that you need to flip the sign when multiplying or dividing by a negative number.
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Manager
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I explained it in kind of a backwards way. The first thing you need to know in that problem is whether x and y are equal. No single statement tells you that. Sorry for the double post, but it seems I can't edit my previous post while viewing the forum with Tapatalk. Sent from my HTC Glacier using Tapatalk 2
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