is 2^x greater than 100? 1. 2^sq.root of x=8 2. 1/2^sq.root : DS Archive
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# is 2^x greater than 100? 1. 2^sq.root of x=8 2. 1/2^sq.root

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is 2^x greater than 100? 1. 2^sq.root of x=8 2. 1/2^sq.root [#permalink]

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09 Nov 2004, 17:03
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is 2^x greater than 100?

1. 2^sq.root of x=8
2. 1/2^sq.root of x <0.01

The answer is D. I understand #1 but i just don't get #2. The explantion says that #2 implies

2^sq.root of x is > 1/.01 or

2^x>100

I dont understand this logic. Can anyone help?
Thanks.

Tim
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09 Nov 2004, 17:23
It's a rule

x>y

implies:

1/x < 1/y

So, in our case:

1/2^sqrt(x) < 1/100

implies

2^sqrt(x) > 100
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09 Nov 2004, 18:52
Try using numbers, for instance

4>2, but if you look at their inverse 1/4<1/2

which demonstrates the rule, x>y => 1/x<1/y
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09 Nov 2004, 19:17
Thank you both. That was a real help!!
DS-Feeling stupid   [#permalink] 09 Nov 2004, 19:17
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# is 2^x greater than 100? 1. 2^sq.root of x=8 2. 1/2^sq.root

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