Is 2|xy^2|> 0? : GMAT Data Sufficiency (DS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 18 Jan 2017, 22:16

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is 2|xy^2|> 0?

Author Message
TAGS:

### Hide Tags

VP
Status: Far, far away!
Joined: 02 Sep 2012
Posts: 1123
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.8
Followers: 181

Kudos [?]: 1963 [5] , given: 219

### Show Tags

05 May 2013, 09:35
5
KUDOS
5
This post was
BOOKMARKED
00:00

Difficulty:

55% (hard)

Question Stats:

49% (01:38) correct 51% (00:41) wrong based on 215 sessions

### HideShow timer Statistics

Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0
[Reveal] Spoiler: OA

_________________

It is beyond a doubt that all our knowledge that begins with experience.

Kant , Critique of Pure Reason

Tips and tricks: Inequalities , Mixture | Review: MGMAT workshop
Strategy: SmartGMAT v1.0 | Questions: Verbal challenge SC I-II- CR New SC set out !! , My Quant

Rules for Posting in the Verbal Forum - Rules for Posting in the Quant Forum[/size][/color][/b]

VP
Status: Final Lap Up!!!
Affiliations: NYK Line
Joined: 21 Sep 2012
Posts: 1096
Location: India
GMAT 1: 410 Q35 V11
GMAT 2: 530 Q44 V20
GMAT 3: 630 Q45 V31
GPA: 3.84
WE: Engineering (Transportation)
Followers: 37

Kudos [?]: 526 [0], given: 70

### Show Tags

05 May 2013, 10:45
Hi
I think the question is flawed....U need to check it again...I may be wrong, If i am than pls correct me!

Consider kudos if my post helps!!!!!

Archit
Manager
Joined: 19 Aug 2012
Posts: 58
Followers: 1

Kudos [?]: 65 [3] , given: 9

### Show Tags

05 May 2013, 10:50
3
KUDOS
B..
so as to confirm that it equation is not equal to zero..
_________________

giving kudos is the best thing you can do for me..

Last edited by anish123ster on 05 May 2013, 13:02, edited 1 time in total.
Intern
Joined: 27 Jul 2012
Posts: 25
Followers: 0

Kudos [?]: 22 [1] , given: 14

### Show Tags

05 May 2013, 12:28
1
KUDOS
B
2nd option is necessary
Just need to see if the expression is not 0.
1 alone cant assure that, but 2 alone can
Senior Manager
Joined: 21 Jan 2010
Posts: 344
Followers: 2

Kudos [?]: 176 [1] , given: 12

### Show Tags

05 May 2013, 14:35
1
KUDOS
The given condition will be true if both x and y are not zero. B clearly states that. Hence B.
Manager
Status: Pushing Hard
Affiliations: GNGO2, SSCRB
Joined: 30 Sep 2012
Posts: 89
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.33
WE: Analyst (Health Care)
Followers: 1

Kudos [?]: 83 [3] , given: 11

### Show Tags

05 May 2013, 19:35
3
KUDOS
Zarrolou wrote:
Is $$2|xy^2|> 0$$?

A)$$x>0$$

B)$$xy>0$$

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!

This Q . asks Is $$2|xy^2|> 0$$? or $$|xy^2|> 0$$?

Statement :: 1 --- > $$x>0$$ .. Dont't Know the value of Y ,.... It can be integer or 0 as well. Therefore, Insufficient.

Statement :: 2--- > $$xy>0$$ ........ This means that either of them has +ve signs or -ve signs. Because for both the cases the condition ...$$xy>0$$ must be true. & if we use these values in the Q, stem... The result must be same for both the signs. Therefore, Sufficient.

Hence ................ B .
_________________

If you don’t make mistakes, you’re not working hard. And Now that’s a Huge mistake.

VP
Status: Final Lap Up!!!
Affiliations: NYK Line
Joined: 21 Sep 2012
Posts: 1096
Location: India
GMAT 1: 410 Q35 V11
GMAT 2: 530 Q44 V20
GMAT 3: 630 Q45 V31
GPA: 3.84
WE: Engineering (Transportation)
Followers: 37

Kudos [?]: 526 [1] , given: 70

### Show Tags

05 May 2013, 20:13
1
KUDOS
missed the point that y could be equal to 0....Of course anopther vote for B

Archit
Verbal Forum Moderator
Joined: 10 Oct 2012
Posts: 630
Followers: 80

Kudos [?]: 1118 [1] , given: 136

### Show Tags

05 May 2013, 21:05
1
KUDOS
Zarrolou wrote:
Is $$2|xy^2|> 0$$?

A)$$x>0$$

B)$$xy>0$$

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!

The question is asking , IS a mod quantity >0? This will always be true, unless there is a possibility that this mod quantity CAN be zero.

From F.S 1, we know that only x>0. y can be 0, in which case we get a NO and y can be a non-zero number, in which case we get a YES. Insufficient.

From F.S 2, we know that xy>0. Thus, both x and y are non-zero numbers. Sufficient.

B.
_________________
Intern
Joined: 05 May 2013
Posts: 12
Followers: 0

Kudos [?]: 2 [1] , given: 6

### Show Tags

06 May 2013, 02:00
1
KUDOS
Answer is B. for S1, the left side cannot be less than zero but certainly it can be zero if y = 0.
VP
Status: Far, far away!
Joined: 02 Sep 2012
Posts: 1123
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.8
Followers: 181

Kudos [?]: 1963 [0], given: 219

### Show Tags

06 May 2013, 02:22
Good job guys!

The OA in indeed B.

$$|abs|$$ can be $$\geq{0}$$, so to make sure that is $$>$$ we need to enstablish that both x,y are $$\neq{0}$$

B does just that
_________________

It is beyond a doubt that all our knowledge that begins with experience.

Kant , Critique of Pure Reason

Tips and tricks: Inequalities , Mixture | Review: MGMAT workshop
Strategy: SmartGMAT v1.0 | Questions: Verbal challenge SC I-II- CR New SC set out !! , My Quant

Rules for Posting in the Verbal Forum - Rules for Posting in the Quant Forum[/size][/color][/b]

Senior Manager
Joined: 21 Jan 2010
Posts: 344
Followers: 2

Kudos [?]: 176 [0], given: 12

### Show Tags

08 May 2013, 12:37
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0

Absolute values are always greater than equal to zero. So, the question is asking if both x and y are not zero.
1)No mention of y .
2)Both are positive or negative but not zero. That's what we want to know. SUFFICIENT.
Manager
Joined: 03 Mar 2013
Posts: 91
Location: India
Concentration: General Management, Marketing
GPA: 3.49
WE: Web Development (Computer Software)
Followers: 0

Kudos [?]: 8 [0], given: 6

### Show Tags

16 May 2013, 08:22
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0

Stmt 1 is not sufficient,
consider stmt2: sy is positive so no matter what ever may be the value of x, its in mod so its positive :: sufficient.
Intern
Joined: 31 May 2013
Posts: 14
Followers: 0

Kudos [?]: 2 [0], given: 31

### Show Tags

23 Jun 2013, 07:38

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0
VP
Status: Far, far away!
Joined: 02 Sep 2012
Posts: 1123
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.8
Followers: 181

Kudos [?]: 1963 [0], given: 219

### Show Tags

23 Jun 2013, 07:45
shivdeepmodi wrote:

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0

No matter what sign $$xy^2$$ has, when we apply the mod it will become positive.

There is only one case in which this does not happen, and it's the case where $$xy=0$$ => $$|xy^2|=0$$.
With option B we are sure that neither x nor y is zero, so the expression $$2|xy^2|$$ will be positive.

There is no need to open the abs value, all we need to check is whether x and y are not zero numbers => B does that and it's sufficient.

Hope it's clear
_________________

It is beyond a doubt that all our knowledge that begins with experience.

Kant , Critique of Pure Reason

Tips and tricks: Inequalities , Mixture | Review: MGMAT workshop
Strategy: SmartGMAT v1.0 | Questions: Verbal challenge SC I-II- CR New SC set out !! , My Quant

Rules for Posting in the Verbal Forum - Rules for Posting in the Quant Forum[/size][/color][/b]

Current Student
Joined: 06 Sep 2013
Posts: 2035
Concentration: Finance
GMAT 1: 770 Q0 V
Followers: 62

Kudos [?]: 593 [0], given: 355

### Show Tags

15 Sep 2013, 15:38
Is 2|xy^2|> 0?

(1) x > 0
(2) xy > 0

Can anyone try this and explain his or her approach?

Many thanks
Intern
Joined: 07 Sep 2013
Posts: 25
Concentration: Entrepreneurship
GMAT 1: Q V
GPA: 3.52
Followers: 0

Kudos [?]: 9 [0], given: 0

### Show Tags

15 Sep 2013, 16:40
Since there's an absolute value symbol in the question, the ONLY time the left side ISN'T > 0 is when it EQUALS 0

So, if x or y = 0, then the answer is NO
If neither x nor y = 0, then the answer is YES

1) x > 0

x is positive, but we don't know about y
If y = 0, then NO
If y = anything else, then YES
Insufficient

2) xy > 0

x and y are either both positive or both negative. Neither can be 0 so the answer is always YES
Sufficient

Choose
[Reveal] Spoiler:
B

t1000
Math Expert
Joined: 02 Sep 2009
Posts: 36548
Followers: 7077

Kudos [?]: 93129 [0], given: 10552

### Show Tags

15 Sep 2013, 23:36
jlgdr wrote:
Is 2|xy^2|> 0?

(1) x > 0
(2) xy > 0

Can anyone try this and explain his or her approach?

Many thanks

Merging similar topics. Please refer to the solutions above.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13441
Followers: 575

Kudos [?]: 163 [0], given: 0

### Show Tags

01 Nov 2014, 15:35
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Is 2|xy^2|> 0?   [#permalink] 01 Nov 2014, 15:35
Similar topics Replies Last post
Similar
Topics:
1 If m ≠ 0 and n ≠ 0, is mn > 0? 4 29 Apr 2016, 02:56
3 If y > 0 is x > 0 ? 2 12 Sep 2015, 11:09
4 If x ≠ 0, is xy > 0? 8 19 Jun 2015, 00:58
2 Is 5 > x > 0 ? 10 28 Feb 2011, 23:18
2 Is x > 0.05? 9 23 Jun 2007, 01:50
Display posts from previous: Sort by