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Is 2|xy^2|> 0?

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Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 09:35
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Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0
[Reveal] Spoiler: OA

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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 10:45
Hi
I think the question is flawed....U need to check it again...I may be wrong, If i am than pls correct me!

Consider kudos if my post helps!!!!!

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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 10:50
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B..
so as to confirm that it equation is not equal to zero..
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Last edited by anish123ster on 05 May 2013, 13:02, edited 1 time in total.
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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 12:28
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B
2nd option is necessary
Just need to see if the expression is not 0.
1 alone cant assure that, but 2 alone can
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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 14:35
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The given condition will be true if both x and y are not zero. B clearly states that. Hence B.
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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 19:35
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Zarrolou wrote:
Is 2|xy^2|> 0?

A)x>0

B)xy>0

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!


This Q . asks Is 2|xy^2|> 0? or |xy^2|> 0?

Statement :: 1 --- > x>0 .. Dont't Know the value of Y ,.... It can be integer or 0 as well. Therefore, Insufficient.

Statement :: 2--- > xy>0 ........ This means that either of them has +ve signs or -ve signs. Because for both the cases the condition ...xy>0 must be true. & if we use these values in the Q, stem... The result must be same for both the signs. Therefore, Sufficient.

Hence ................ B .
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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 20:13
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missed the point that y could be equal to 0....Of course anopther vote for B

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Re: Is 2|xy^2|> 0? [#permalink] New post 05 May 2013, 21:05
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Zarrolou wrote:
Is 2|xy^2|> 0?

A)x>0

B)xy>0

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!


The question is asking , IS a mod quantity >0? This will always be true, unless there is a possibility that this mod quantity CAN be zero.

From F.S 1, we know that only x>0. y can be 0, in which case we get a NO and y can be a non-zero number, in which case we get a YES. Insufficient.

From F.S 2, we know that xy>0. Thus, both x and y are non-zero numbers. Sufficient.

B.
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Re: Is 2|xy^2|> 0? [#permalink] New post 06 May 2013, 02:00
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Answer is B. for S1, the left side cannot be less than zero but certainly it can be zero if y = 0.
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Re: Is 2|xy^2|> 0? [#permalink] New post 06 May 2013, 02:22
Good job guys!

The OA in indeed B.

|abs| can be \geq{0}, so to make sure that is > we need to enstablish that both x,y are \neq{0}

B does just that
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Re: Is 2|xy^2|> 0? [#permalink] New post 08 May 2013, 12:37
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0


Absolute values are always greater than equal to zero. So, the question is asking if both x and y are not zero.
1)No mention of y .
2)Both are positive or negative but not zero. That's what we want to know. SUFFICIENT.
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Re: Is 2|xy^2|> 0? [#permalink] New post 16 May 2013, 08:22
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0

Stmt 1 is not sufficient,
consider stmt2: sy is positive so no matter what ever may be the value of x, its in mod so its positive :: sufficient.
B. is the answer
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Re: Is 2|xy^2|> 0? [#permalink] New post 23 Jun 2013, 07:38
Not clear about B.

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0
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Re: Is 2|xy^2|> 0? [#permalink] New post 23 Jun 2013, 07:45
shivdeepmodi wrote:
Not clear about B.

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0


No matter what sign xy^2 has, when we apply the mod it will become positive.

There is only one case in which this does not happen, and it's the case where xy=0 => |xy^2|=0.
With option B we are sure that neither x nor y is zero, so the expression 2|xy^2| will be positive.

There is no need to open the abs value, all we need to check is whether x and y are not zero numbers => B does that and it's sufficient.

Hope it's clear
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Is 2|xy^2|> 0? [#permalink] New post 15 Sep 2013, 15:38
Is 2|xy^2|> 0?

(1) x > 0
(2) xy > 0

Can anyone try this and explain his or her approach?

Many thanks
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Re: Is 2|xy^2|> 0? [#permalink] New post 15 Sep 2013, 16:40
Since there's an absolute value symbol in the question, the ONLY time the left side ISN'T > 0 is when it EQUALS 0

So, if x or y = 0, then the answer is NO
If neither x nor y = 0, then the answer is YES

1) x > 0

x is positive, but we don't know about y
If y = 0, then NO
If y = anything else, then YES
Insufficient

2) xy > 0

x and y are either both positive or both negative. Neither can be 0 so the answer is always YES
Sufficient

Choose
[Reveal] Spoiler:
B


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Re: Is 2|xy^2|> 0? [#permalink] New post 15 Sep 2013, 23:36
Expert's post
Re: Is 2|xy^2|> 0?   [#permalink] 15 Sep 2013, 23:36
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