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# Is 2x-3y<x^2? 1. 2x-3y=-2 2. x>2 and y>0

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Manager
Joined: 09 Sep 2004
Posts: 165
Followers: 1

Kudos [?]: 1 [0], given: 0

Is 2x-3y<x^2? 1. 2x-3y=-2 2. x>2 and y>0 [#permalink]  22 Nov 2004, 09:16
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is 2x-3y<x^2?

1. 2x-3y=-2
2. x>2 and y>0
Director
Joined: 31 Aug 2004
Posts: 610
Followers: 3

Kudos [?]: 50 [0], given: 0

I don't know what to think about second statement !
y>0 does not provide anything useful IMO

as 2x-3y <0 then x^2 being always >0 is necessarily > 2x-3y

So i pick A
Senior Manager
Joined: 19 Oct 2004
Posts: 318
Location: Missouri, USA
Followers: 1

Kudos [?]: 27 [0], given: 0

D for this one..

statement 1 is clear enough. whatever be the value of x, it will be positive.

statement 2.. whatever be the value of y, x^2 will always be greater.
_________________

Let's get it right!!!!

Senior Manager
Joined: 19 May 2004
Posts: 291
Followers: 1

Kudos [?]: 9 [0], given: 0

Yeah, i go for D too.

twixt, Y>0 is useful:
Now you know that "-3y" only substruct from the left side.
And since x>2, you can also know that 2*x will always be less than x^2.
Director
Joined: 31 Aug 2004
Posts: 610
Followers: 3

Kudos [?]: 50 [0], given: 0

I have the feeling I was asleep in posting this burst of answers...

You're right guys shame on me !
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