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Is 7 < sqrt(n) < 8? (1) n > 50 (2) n < 60 [#permalink]
 06 Mar 2006, 11:49
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Is 7 < sqrt(n) < 8?
(1) n > 50
(2) n < 60
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Manager
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hellom3p wrote: Is 7 < sqrt(n) < 8?
(1) n > 50
(2) n < 60
7 < sqrt(n) < 8
square
49 < n < 64
therefore you will need both
so is C
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Manager
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what about
-8<sqrt (n)<-7?
49<n<64
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Senior Manager
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hellom3p wrote: what about
-8<sqrt (n)<-7?
49<n<64
Question is not asking for -ve values.
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Manager
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I am for E.
What about fractions. Then n can be between 49 and 50 too. Comments please...
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Tricky one)) E for me cause we don't know if n is an integer))
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Manager
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Even if n was a fraction, wouldnt sqrt(n) still lie between 7 and 8 if we take both the statements together? Yurik79 could you elaborate? I mean if n was 55.5 then sqrt(55.5) would still be between 7 and 8 right? Am I missing something here?
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Gordon wrote: Even if n was a fraction, wouldnt sqrt(n) still lie between 7 and 8 if we take both the statements together? Yurik79 could you elaborate? I mean if n was 55.5 then sqrt(55.5) would still be between 7 and 8 right? Am I missing something here?
No, you are not missing anything 
Even if we consider fractions between 7 & 8, "C" holds good!
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gmat_crack wrote: hellom3p wrote: what about
-8<sqrt (n)<-7?
49<n<64 Question is not asking for -ve values. why not?
it's like asking:
Is sqrt(n) negative?
I. n = 49
II. n = 64
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Manager
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Guys, please explain me.
What if n = 49.5? sqrt(n) will still be between 7 and 8.
So, shouldn't the domain of n be (49,64) exluding 49 and 64?
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chuckle wrote: Guys, please explain me.
What if n = 49.5? sqrt(n) will still be between 7 and 8.
So, shouldn't the domain of n be (49,64) exluding 49 and 64?
chuckle,
The question asks whether, 7 < sqrt(n) < 8? given that n>50 & n < 60.
From the given two conditions it lies between that range.
You are right, sqrt(49.5) will still lie between 7 & 8 (it is 7.02..) but that is not what this DS asks, it just wants us to tell,
if n>50 & n < 60, is 7 < sqrt(n) < 8 true?
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Thanks Vivek. I understood now.
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hellom3p wrote: gmat_crack wrote: hellom3p wrote: what about
-8<sqrt (n)<-7?
49<n<64 Question is not asking for -ve values. why not? it's like asking: Is sqrt(n) negative? I. n = 49 II. n = 64 E seems correct to me cuz even if 49<n<64, sqrt(n) can be +ve and -ve. so sqrt can or canot fall between 7 and 8.
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I will also go with E as
a) n > 50 - obviously insufficient
b) n < 60 - obviously insufficient
a & b) for every n (where 50 < n < 60), sqrt(n) is either +ve or -ve - so insufficient.
OA please!
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On the GMAT , the sqrt is always positive. sqrt(4) is always 2 and not -2.
In my opinion, that is $@#%$%$%, but we need to keep that in mind for such problems.
Professor wrote: hellom3p wrote: gmat_crack wrote: hellom3p wrote: what about
-8<sqrt (n)<-7?
49<n<64 Question is not asking for -ve values. why not? it's like asking: Is sqrt(n) negative? I. n = 49 II. n = 64 E seems correct to me cuz even if 49<n<64, sqrt(n) can be +ve and -ve. so sqrt can or canot fall between 7 and 8. |
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lhotseface wrote: On the GMAT , the sqrt is always positive. sqrt(4) is always 2 and not -2.
In my opinion, that is $@#%$%$%, but we need to keep that in mind for such problems.
Oh! I did not know about this at all.  Any ways can you please tell me is this a general thumb rule for all DS questions or it applies to the whole quantitative section?
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7 < sqrt(n) < 8
49 < n < 64
(1) Insufficient. n could be 100 and sqrt(n) would be out of range
(2) Insufficient for the same reason
Using (1) and (2), we know 50 < n < 60 which lies within the range.
Ans C
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