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Is 7^X > 100 ? (1) 7^(X+2) > 9800 (2) 7^2X > 100,00

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Is 7^X > 100 ? (1) 7^(X+2) > 9800 (2) 7^2X > 100,00 [#permalink]

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New post 12 May 2010, 20:00
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Is 7^X > 100 ?

(1) 7^(X+2) > 9800
(2) 7^2X > 100,00


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-H
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Manager
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Re: DS [#permalink]

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New post 12 May 2010, 21:15
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1. 7^(x+2)> 9800

or 7^x * 7^2 > 9800
or 7^x > 9800 / 49
or 7^x > 200 ------> 7^x > 100

Therefore , sufficient.

2. 7^2X > 100,00

or (7^x)^2 > 10000
or (7^x)^2 - (100)^2 > 0 ----> a^2 - b^2 >0
implies 7^x > 100 or 7^x <-100

Therefore not sufficient.

Ans : A
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Re: DS [#permalink]

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New post 13 May 2010, 03:26
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harikattamudi wrote:
Is 7^X > 100 ?

(1) 7^(X+2) > 9800
(2) 7^2X > 100,00


Thanks
-H

Is it D?
(1): suff
(2): (7^x)^2>100,00 so 7^x>100. 7^x cannot be negative
Manager
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Re: DS [#permalink]

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New post 13 May 2010, 06:45
"7^x <-100"

ok this is not possibt because 7^x can not be negative
Manager
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Re: DS [#permalink]

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New post 14 May 2010, 00:59
yes agree.. thanks for correcting...
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Re: DS [#permalink]

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New post 15 May 2010, 09:34
7^x cannot be -ive hence the ans is D
Re: DS   [#permalink] 15 May 2010, 09:34
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