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Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b <

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u2lover
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Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   08 Aug 2006, 19:00
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A
B
C
D
E

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Is |a| + |b| > |a + b| ?

(1) a^2 > b^2

(2) |a| × b < 0

please explain



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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   08 Aug 2006, 19:30
u2lover wrote:
Is |a| + |b| > |a + b| ?

(1) a^2 > b^2

(2) |a| × b < 0

please explain



I've got (E)

ST1. a^2>b^2

Case1: a=2,b=1 => 3=3
Case2: a=2,b=-1 => 3>1
Not SUFF

ST2. |a|b<0 => b<0

Still not suff
Case1: a=1,b=-1
Case2: a=-1,b=-1

Combining, still not suff

Case1: a=2,b=-1
Case2: a=-2,b=-1

So, (E)
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   08 Aug 2006, 19:58
E. we donot know the signs of a and b.
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   08 Aug 2006, 21:48
Quote:
Is |a| + |b| > |a + b| ?

(1) a^2 > b^2

(2) |a| × b < 0


E ...
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   08 Aug 2006, 23:37
Must be E. Signs of both a and b are required. Statement 2 tells only the sign of b. Statement 1 just tells that a=b is false.
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   09 Aug 2006, 04:12
Isn't the answer B ?

Please correct me if I am wrong

Stmt 2
(1) a^2 > b^2 InSufficient

(2) |a| × b < 0

Lets assume a is +ve
Then we get ab < 0 , Since a is +ve , b must be negative for the condition to be true


Now lets assume a -ve
then we get -ab<0 , Since a is negative , b must + ve for the condition to be true

Since a and b are opposite signs
|a| + |b| > |a + b|
try with 2,-3
|-2| + |3| > |-2 + 3|

or -2,3
|2| + |-3| > |2 - 3|
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   09 Aug 2006, 20:06
ivymba wrote:
Isn't the answer B ?

Please correct me if I am wrong

Stmt 2
(1) a^2 > b^2 InSufficient

(2) |a| × b < 0

Lets assume a is +ve
Then we get ab < 0 , Since a is +ve , b must be negative for the condition to be true


Now lets assume a -ve
then we get -ab<0 , Since a is negative , b must + ve for the condition to be true


If a is -ve, then |a| is +ve .. The 2nd statement tells us that b is -ve, but no information can be deduced abt a.
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   11 Aug 2006, 03:10
E

1) when a = 3 and b = 2
then |a| + |b| = |a+b|

When a = -3 and b = 2
then |a| + |b| > |a+b|

Not suff

2) b is negative.
When a = 3 and b = -2
then |a| + |b| > |a+b|
when a = -3 and b = -2
then |a| + |b| = |a+b|
Not suff

Together
Same as 2. Not suff.
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   11 Aug 2006, 07:52
St 1 tells no sign for a and b.
St 2 tells sign for only b

E
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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink] New post   11 Aug 2006, 09:30
yup...E we dont know the sign of a



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Re: Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b < [#permalink]
11 Aug 2006, 09:30
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