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Is a*b*c divisible by 32?

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Is a*b*c divisible by 32? [#permalink] New post 24 May 2007, 00:48
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

46% (02:19) correct 54% (01:17) wrong based on 33 sessions
Is a*b*c divisible by 32?

(1) a, b and c are consecutive even integers.

(2) a*c < 0
[Reveal] Spoiler: OA

Last edited by Juaz on 24 May 2007, 01:16, edited 1 time in total.
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Re: Is a*b*c divisible by 32? [#permalink] New post 24 May 2007, 01:05
answer: E

strategies:
1-Chose #s -best way

Last edited by UMB on 24 May 2007, 07:43, edited 1 time in total.
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Re: Is a*b*c divisible by 32? [#permalink] New post 24 May 2007, 01:17
addendum: a number is divisible by 8 if it can be divided 3 times by 2
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Re: Is a*b*c divisible by 32? [#permalink] New post 24 May 2007, 02:03
Answer has to be E .

1) lets say A=2 , B=4 and C=6 , then abc is not divisible by 32 . However if A=4 , B=6 and C=8 , abc is divisible by 32.So insufficient

2) a= 5 , c= -1 , b= 3 --> abc is not divisible by 32
a= 4 , c = -4 , b= 2 ---> abc is divisible by 32 . So insufficient

1 and 2 together
A= -2 , B=0 , C=2 , abc=0 so again insufficient.
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Re: Is a*b*c divisible by 32? [#permalink] New post 24 May 2007, 10:04
OA is C, as 0 is divisible by 32.
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Re: Is a*b*c divisible by 32? [#permalink] New post 25 May 2007, 01:39
I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?
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Re: Is a*b*c divisible by 32? [#permalink] New post 25 May 2007, 02:33
abhinava wrote:
I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?


read more at:

http://mathforum.org/library/drmath/view/60913.html

I don't know if thats the GMAT official viewpoint.

:-D
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Re: Is a*b*c divisible by 32? [#permalink] New post 25 May 2007, 05:10
Juaz wrote:
Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0


*Question edited.


OA is correct. Its C.

Zero divided by a negative or positive number is either zero or is expressed as a fraction with zero as numerator and the finite quantity as denominator.

Source:- http://en.wikipedia.org/wiki/0_(number #Extended_use_of_zero_in_mathematics
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Re: Is a*b*c divisible by 32? [#permalink] New post 25 May 2007, 15:02
Statement I: insufficient but helpful

Statement two says that a*c <0 so one of the numbers must be negative, all could be negative as well:

-8 * -6 * -4 = -192 which is divisible by 32 as per GMAT definition y=xq+r when q and r are unique integers and 0<=r<x ( -192=32*-6 + 0)

-6*-4*-2 =-48 which is not divisible by 32.

insufficient.

Taken together we have that they are consecutive, and that one is negative and the other is not. Because of the restriction of being consecutive and even we have only one possible set of numbers: -2,0,2.

abc =0. 0 is divisable by any integer except zero. so the answer was C.

tricky problem and I would have no doubt gotten this wrong on the test if i didn't have 10 minutes to sit and think about it
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Re: Is a*b*c divisible by 32? [#permalink] New post 21 Oct 2014, 07:14
Juaz wrote:
Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0


*Question edited.



What on earth question ?

Statements (1) and (2) combined are sufficient. From S1 + S2 it follows that either a or c is negative. As a , b, and C are consecutive even integers, one of these three numbers must be 0. Thus, abc=0 which is divisible by 32

and what on earth explanation ! Mind blown!!! :x :x :x
Re: Is a*b*c divisible by 32?   [#permalink] 21 Oct 2014, 07:14
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