arjtryarjtry wrote:

Is A + B + C even?

1. A - C - B is even

2. {A - C}/B is odd

1. A - C - B is even

A - C - B =2k

A= 2K+B+C

A + B + C = 2K+B+C +B + C = 2(K+B+C) always even.

(assuming A, B,C are integers.)

Suffcient

2. {A - C}/B is odd

{A - C}/B =(2k+1)

A = B ((2k+1)+C

A + B + C = B ((2k+1)+C +B+C = 2Bk + 2(B+C) always even

suffcient

D

My solution is correct only if A, B,C are integers (I already mention that in the first post)

Is OA is E?

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