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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
08 Apr 2012, 08:30

2

This post received KUDOS

Expert's post

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
29 Jul 2012, 05:57

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

This question has more than I trap. Thanks for the explanation, Bunnel...!

_________________

The world ain't all sunshine and rainbows. It's a very mean and nasty place and I don't care how tough you are it will beat you to your knees and keep you there permanently if you let it. You, me, or nobody is gonna hit as hard as life. But it ain't about how hard ya hit. It's about how hard you can get it and keep moving forward. How much you can take and keep moving forward. That's how winning is done!

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
29 Sep 2012, 21:44

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

Hi Bunuel,

Is this question, a good gmat candidate or not.

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Re: Is A + B + C even? [#permalink]
29 Sep 2012, 23:53

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

Bunuel.. how can B will be even if it wud be mentioned that a b c are integers???

_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Re: Is A + B + C even? [#permalink]
01 Oct 2012, 04:40

Expert's post

sanjoo wrote:

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

Bunuel.. how can B will be even if it wud be mentioned that a b c are integers???

Sorry, but I don't understand your question at all. Can you please elaborate what you mean? Thank you.

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
01 Oct 2012, 08:29

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers thena+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ...

_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
11 Oct 2012, 09:54

sanjoo wrote:

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \frac{a-c}{b}=odd. The same here: if the variables are integers thena+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ...

It goes like this:

Q: Is A+B+C= EVEN

S1: A-B-C= Even i.e. We can write A-B-C= 2N =>A=2N + B+C Substituting in the main equation we get

2N+2(B+C)=2[N+B+C]

Now, N is an Integer, but we dont know whether, B+C= Integer or not. Hence N+B+C mayor may not be an Integer. Therefore, S1 is insufficient.

Same case with Statement 2, which on simplification gives, A=(2N+1)B + C => A+B+C= 2(B+C+NB)

Again same same scenario, We are not aware whether, the value in the parenthesis is an Integer or not.

Hence, S2 is also Insufficient.

S1 & S2 together also does not resolve the issue of whether B+C is integer or not.