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Is A + B + C even? [#permalink]
 08 Apr 2012, 08:17
Question Stats:
19% (01:58) correct
80% (01:25) wrong based on 1 sessions
Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is odd
Last edited by Bunuel on 29 Jul 2012, 07:01, edited 2 times in total.
Edited the question
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Re: Odd/Even (Ultra hard) from Math Flashcard [#permalink]
08 Apr 2012, 08:41
I think the OA is incorrect.
1)A-B-C can only be even, if either all are even or two are odd and one is even, in both cases a+b+c is even.
2) (A-C)/B can be odd if all are even or if all are odd, so A+B+C is even or odd, which makes the statement insufficient.
IMO A is correct.
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
08 Apr 2012, 09:30
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catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E.
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
08 Apr 2012, 09:53
Hi +1 E This is explained in the GMAT Club notes. I suggest you refer the Club Notes, cause when i first took a crack at this I choose A as well.
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
29 Jul 2012, 06:57
Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. This question has more than I trap. Thanks for the explanation, Bunnel...!
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
29 Sep 2012, 22:44
Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. Hi Bunuel, Is this question, a good gmat candidate or not.
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Re: Is A + B + C even? [#permalink]
30 Sep 2012, 00:53
Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. Bunuel.. how can B will be even if it wud be mentioned that a b c are integers???
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Re: Is A + B + C even? [#permalink]
01 Oct 2012, 05:40
sanjoo wrote: Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. Bunuel.. how can B will be even if it wud be mentioned that a b c are integers??? Sorry, but I don't understand your question at all. Can you please elaborate what you mean? Thank you.
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
01 Oct 2012, 09:29
Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ...
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]
11 Oct 2012, 10:54
sanjoo wrote: Bunuel wrote: catty2004 wrote: Is A + B + C even?
(1) A - C - B is even
(2) (A - C)/B is odd Notice that we are not told that a, b and c are integers. Q: is a+b+c=even? (1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not, for example if a=3.5, b=1, c=0.5 then a-c-b=2=even, but a+b+c=5=odd. Not sufficient. (2) \frac{a-c}{b}=odd. The same here: if the variables are integers then a+b+c will be even but if they are not for example if a=3.5, b=1, c=0.5 then \frac{a-c}{b}=3=odd, but a+b+c=5=odd. Not sufficient (1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient. Answer: E. I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ... It goes like this: Q: Is A+B+C= EVEN S1: A-B-C= Even i.e. We can write A-B-C= 2N =>A=2N + B+C Substituting in the main equation we get 2N+2(B+C)=2[N+B+C] Now, N is an Integer, but we dont know whether, B+C= Integer or not. Hence N+B+C mayor may not be an Integer. Therefore, S1 is insufficient. Same case with Statement 2, which on simplification gives, A=(2N+1)B + C => A+B+C= 2(B+C+NB) Again same same scenario, We are not aware whether, the value in the parenthesis is an Integer or not. Hence, S2 is also Insufficient. S1 & S2 together also does not resolve the issue of whether B+C is integer or not. Hence answer is E. I hope this is clear. Thanks 
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Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is
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11 Oct 2012, 10:54
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