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Is a*b*c is divisible by 32? 1. a,b and c are consecutive

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Is a*b*c is divisible by 32? 1. a,b and c are consecutive [#permalink] New post 24 May 2007, 00:48
00:00
A
B
C
D
E

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50% (02:30) correct 50% (00:01) wrong based on 0 sessions
Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0


*Question edited.

Last edited by Juaz on 24 May 2007, 01:16, edited 1 time in total.
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 [#permalink] New post 24 May 2007, 01:05
answer: E

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1-Chose #s -best way

Last edited by UMB on 24 May 2007, 07:43, edited 1 time in total.
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 [#permalink] New post 24 May 2007, 01:17
addendum: a number is divisible by 8 if it can be divided 3 times by 2
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 [#permalink] New post 24 May 2007, 02:03
Answer has to be E .

1) lets say A=2 , B=4 and C=6 , then abc is not divisible by 32 . However if A=4 , B=6 and C=8 , abc is divisible by 32.So insufficient

2) a= 5 , c= -1 , b= 3 --> abc is not divisible by 32
a= 4 , c = -4 , b= 2 ---> abc is divisible by 32 . So insufficient

1 and 2 together
A= -2 , B=0 , C=2 , abc=0 so again insufficient.
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 [#permalink] New post 24 May 2007, 10:04
OA is C, as 0 is divisible by 32.
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 [#permalink] New post 25 May 2007, 01:39
I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?
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 [#permalink] New post 25 May 2007, 02:33
abhinava wrote:
I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?


read more at:

http://mathforum.org/library/drmath/view/60913.html

I don't know if thats the GMAT official viewpoint.

:-D
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Re: DS - even integers [#permalink] New post 25 May 2007, 05:10
Juaz wrote:
Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0


*Question edited.


OA is correct. Its C.

Zero divided by a negative or positive number is either zero or is expressed as a fraction with zero as numerator and the finite quantity as denominator.

Source:- http://en.wikipedia.org/wiki/0_(number #Extended_use_of_zero_in_mathematics
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 [#permalink] New post 25 May 2007, 15:02
Statement I: insufficient but helpful

Statement two says that a*c <0 so one of the numbers must be negative, all could be negative as well:

-8 * -6 * -4 = -192 which is divisible by 32 as per GMAT definition y=xq+r when q and r are unique integers and 0<=r<x ( -192=32*-6 + 0)

-6*-4*-2 =-48 which is not divisible by 32.

insufficient.

Taken together we have that they are consecutive, and that one is negative and the other is not. Because of the restriction of being consecutive and even we have only one possible set of numbers: -2,0,2.

abc =0. 0 is divisable by any integer except zero. so the answer was C.

tricky problem and I would have no doubt gotten this wrong on the test if i didn't have 10 minutes to sit and think about it
  [#permalink] 25 May 2007, 15:02
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