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Is a*b*c is divisible by 32? 1. a,b and c are consecutive

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Is a*b*c is divisible by 32? 1. a,b and c are consecutive [#permalink]  24 May 2007, 00:48
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Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0

*Question edited.

Last edited by Juaz on 24 May 2007, 01:16, edited 1 time in total.
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Last edited by UMB on 24 May 2007, 07:43, edited 1 time in total.
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addendum: a number is divisible by 8 if it can be divided 3 times by 2
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Answer has to be E .

1) lets say A=2 , B=4 and C=6 , then abc is not divisible by 32 . However if A=4 , B=6 and C=8 , abc is divisible by 32.So insufficient

2) a= 5 , c= -1 , b= 3 --> abc is not divisible by 32
a= 4 , c = -4 , b= 2 ---> abc is divisible by 32 . So insufficient

1 and 2 together
A= -2 , B=0 , C=2 , abc=0 so again insufficient.
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OA is C, as 0 is divisible by 32.
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I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?
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abhinava wrote:
I doubt the OA. I am not sure if 0 is divisible by any number.Can anyone throw some light on this?

http://mathforum.org/library/drmath/view/60913.html

I don't know if thats the GMAT official viewpoint.

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Re: DS - even integers [#permalink]  25 May 2007, 05:10
Juaz wrote:
Is a*b*c is divisible by 32?

1. a,b and c are consecutive even integers.

2. a*c < 0

*Question edited.

OA is correct. Its C.

Zero divided by a negative or positive number is either zero or is expressed as a fraction with zero as numerator and the finite quantity as denominator.

Source:- http://en.wikipedia.org/wiki/0_(number #Extended_use_of_zero_in_mathematics
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Statement two says that a*c <0 so one of the numbers must be negative, all could be negative as well:

-8 * -6 * -4 = -192 which is divisible by 32 as per GMAT definition y=xq+r when q and r are unique integers and 0<=r<x ( -192=32*-6 + 0)

-6*-4*-2 =-48 which is not divisible by 32.

insufficient.

Taken together we have that they are consecutive, and that one is negative and the other is not. Because of the restriction of being consecutive and even we have only one possible set of numbers: -2,0,2.

abc =0. 0 is divisable by any integer except zero. so the answer was C.

tricky problem and I would have no doubt gotten this wrong on the test if i didn't have 10 minutes to sit and think about it
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