Joined: 16 Jun 2010
[, given: 0] 2
is a >b: st1 a/b=7/10 st2 a=70/100 b [
25 Aug 2010, 01:11
how would you approach this one
thanks for your help
is a >b
st2 a=70/100 b
Joined: 02 Apr 2010
[, given: 0] 18
This type of problem is probably solved fastest by picking numbers. The key is to think about positive and negative numbers.
Statement 1: Cross-multiply to obtain 10*a = 7*b This will hold true e.g. if a = 7 and b = 10 => a < b, but also if a= -7 and b = -10 => a > b. Hence, statement A is not sufficient. Statement 2: I assume the statement reads a = (70 / 100)*b, otherwise it would contradict the first statement. Again cross-multiple and simplify the fraction to obtain 10*a = 7*b. The second statement doesn't provide you with any additional information. Thus, E is the solution to this problem.
Joined: 15 Apr 2010
[, given: 0] 29
both statements essentially say the same thing.. ratio: a:b=7:10 => 10a=7b;
now just plug in some values to see if you can get any definitive answers: assume a=7, b=10 or a=14, b=20 and so on.... (a< b) but there are negative answers as well.... a=-7, b=-10 => a > b I would go with E.....