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Is (a/d)*(b/e)*(c/f) > (b/d)*(c/e) ? (1) bc > de (2) a

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Is (a/d)*(b/e)*(c/f) > (b/d)*(c/e) ? (1) bc > de (2) a [#permalink] New post 02 Dec 2004, 15:48
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B
C
D
E

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Is (a/d)*(b/e)*(c/f) > (b/d)*(c/e) ?

(1) bc > de
(2) a > f


PS: Very Sorry, I edited this to correct the first term to (a/d) - instead of (a/b).
I'll double check next time.

Last edited by forumsmba on 03 Dec 2004, 14:44, edited 1 time in total.
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 [#permalink] New post 02 Dec 2004, 17:16
answer is E, unless they give you more detail as to what a,b & c are.
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Re: DS: Ratios [#permalink] New post 03 Dec 2004, 07:35
forumsmba wrote:
Is (a/b)*(b/e)*(c/f) > (b/d)*(c/e) ?

(1) bc > de
(2) a > f


hi. is this written right? Should the first part be (a/b)(d/e)(c/f)? If so, then the answer is B. If not, then I think the answer is E.
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 [#permalink] New post 03 Dec 2004, 16:48
I think the answer is E even if the first part is (a/b)(d/e)(c/f), because even if (b/d)*(c/e) cancels out,

In stat 2, we don't know if f is a negative number and a is a positive thus we cannot determine the inequality. If the question states that a,b,c,d,e,f are all positive or all negative then the answer is B.
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 [#permalink] New post 04 Dec 2004, 16:10
OA is E.

nzgmat, I think you are missing a key point. Even if the question states a & f are positive, I believe that answer should be E.

The reason: You cannot cancel terms on either side of < or > without knowing if they are positive

-5*a < -5*f means: a>f
5*a < 5*f means: a<f

Correct me if I am wrong.
-fm
  [#permalink] 04 Dec 2004, 16:10
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