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# Is A positive? 1. x^2 - 2x + A is positive for all x 2.

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CEO
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Is A positive? 1. x^2 - 2x + A is positive for all x 2. [#permalink]

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20 Dec 2007, 08:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is A positive?

1. x^2 - 2x + A is positive for all x
2. A*x^2 + 1 is positive for all x
CEO
Joined: 17 Nov 2007
Posts: 3589
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
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Kudos [?]: 3550 [0], given: 360

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20 Dec 2007, 15:42
I guess A

1. y=x^2 - 2x +A>0. min(y)=1-2+A>0, A>1. SUFF.
2. A*x^2 + 1 >0. A>=0. 0 - is not positive number. (?) INSUFF.

I'm not sure about bold statement.
Manager
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20 Dec 2007, 19:21
Tough, but my guess will be between C or E:

I. Insuff: if x = 1: 1 - 2 + A >0
A > 1
if x = 0: a > 0
if x = 3: 9 - 6 + A > 0, where A could be -ve

II. Insuff:
A * x^2 > -1
A > -1/x^2
where A could be -ve and +ve

At the end I try educated guess =) and vote for E
Director
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Re: positive A [#permalink]

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21 Dec 2007, 21:30
bmwhype2 wrote:
Is A positive?

1. x^2 - 2x + A is positive for all x
2. A*x^2 + 1 is positive for all x

From (i)
A > 2x-x^2

say,x=5
A>-15

A might be negative.

And for other values of X it might be positive.

(i) is insufficient.

From (ii)

A > -1/x^2

A can be positive as well as negative.

Thus answer should be "E".
CEO
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Concentration: Entrepreneurship, Other
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22 Dec 2007, 00:35
1. x^2 - 2x + A is positive for all x

I think you forget about "all x"
CEO
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22 Dec 2007, 19:51
i felt this was a hard one.

OA is A
CEO
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22 Dec 2007, 19:57
walker wrote:
I guess A

1. y=x^2 - 2x +A>0. min(y)=1-2+A>0, A>1. SUFF.
2. A*x^2 + 1 >0. A>=0. 0 - is not positive number. (?) INSUFF.

I'm not sure about bold statement.

in min(y), how do u know that x is an integer?
CEO
Joined: 17 Nov 2007
Posts: 3589
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
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Kudos [?]: 3550 [0], given: 360

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22 Dec 2007, 23:47
bmwhype2 wrote:
in min(y), how do u know that x is an integer?

I use fast method (out of GMAT) to find extreme (minimum) of parabola:

f(x)=x^2 - 2x +A
f'(x)=2x-2=0 ==> x=1
f(x=1)=1-2+A=A-1, So A-1 must be positive and A>1
SVP
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23 Dec 2007, 01:00
Another way can be to search for Delta and to make it negative (no roots)

x^2 - 2x + A

Delta = b^2 - 4*a*c
= (-2)^2 -4*(1)*A
= 4*(1-A)

x^2 - 2x + A remains positive, of the sign of 1*x^2, if and only if Delta < 0

Thus,
4*(1-A) < 0
<=> A > 1

SVP
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23 Dec 2007, 01:28
walker wrote:
Fig wrote:
Another way can be to search for Delta and to make it negative (no roots)

Nice way!

Your's as well
23 Dec 2007, 01:28
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# Is A positive? 1. x^2 - 2x + A is positive for all x 2.

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