1. Is lxl <1>1; -1<x<1; x<-1
Solving for each case, x=3 or 1/3. Insufficient.
Stmt 2: |x| ≠ 3. Insufficient.
Both together. x=1/3. sufficient.
i have not worked on many absolute value problems, so i please let me know what i am doing anything wrong, taking extra steps, etc.
from the question stem |x|<1 = is x<1, x<-1
|x+1| = 2|x-1|
for both positive x:
x+1 = 2x-2 .... x=3
for both negative x:
-x+1 = -2x-2 ... x=-3
Now my first question is, is there anyway to skip this step? it is an ainvalid answer I noticed no one computed it...
For +/- combinations
x+1= -2x-2 ... x=-1 another invalid answer.
-x+1 = 2x-2 ... x=1... ditto
So obviously I did something wrong because I did not come up with 1/3 for any of the answers...