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# Is |n| < 1 ? (1) nx n < 0 (2) x 1 = 2

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Director
Joined: 12 Jun 2006
Posts: 539
Followers: 1

Kudos [?]: 11 [0], given: 1

Is |n| < 1 ? (1) nx n < 0 (2) x 1 = 2 [#permalink]  29 Dec 2006, 16:36
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Is |n| < 1 ?

(1) nx â€“ n < 0

(2) xâ€“1 = â€“2
Senior Manager
Joined: 23 Jun 2006
Posts: 389
Followers: 1

Kudos [?]: 300 [0], given: 0

E

try n=1/2 and n=2 with x=-1

both values saisfy both st1 and st2, but give different answer to question.
hence insufficient.
Manager
Joined: 04 Nov 2006
Posts: 159
Followers: 3

Kudos [?]: 6 [0], given: 0

Looks like the answer is E. Both together are insufficient.

1) Without knowing anything about the value of x, this is insufficient.
2) Tells you that x = -1, but nothing else. So insufficient.

1 & 2) By using the value of x in the inequality, we get n > 0. Insufficient.

Are you sure you copied this problem correctly? There's a problem on the first page of the Manhattan GMAT site that's similar to this except x is an exponent in statement 1 and -1 is an exponent in statement 2.
VP
Joined: 28 Mar 2006
Posts: 1390
Followers: 2

Kudos [?]: 18 [0], given: 0

Re: DS Prob [#permalink]  29 Dec 2006, 16:54
ggarr wrote:
Is |n| < 1 ?

(1) nx â€“ n < 0

(2) xâ€“1 = â€“2

From (I) n(x-1) < 0 then

either n<0 and (x-1)>0
or n>0 and (x-1) <0

INSUFF

From(2) x-1 = -2 INSUFF

From(I) and (II) we can derive that n is +ve since (x-1) =-2

But we cannot say if n<1 or >1

So E
Senior Manager
Joined: 24 Nov 2006
Posts: 352
Followers: 1

Kudos [?]: 11 [0], given: 0

Yep. Even if we use (1) and (2) together, |n| could be < or > 1. Thus E.
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