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Is n an integer? 1) n^2 is an integer 2)SQRT(n) is an

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Is n an integer? 1) n^2 is an integer 2)SQRT(n) is an [#permalink] New post 31 May 2006, 18:32
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A
B
C
D
E

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Is n an integer?

1) n^2 is an integer
2)SQRT(n) is an integer


Please give explanations with answer. thanks

Last edited by buckkitty on 01 Jun 2006, 13:28, edited 1 time in total.
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Re: DS-OG #146 [#permalink] New post 31 May 2006, 18:56
buckkitty wrote:
Is n an integer?

1) n^2
2)SQRT(n) is an integer


st 1 is incomplete.
st 2 is suff.

so B or D.
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 [#permalink] New post 31 May 2006, 19:25
Going by what's given in statement 2, if I have to guess the remaining part of statement 1 it should be "n^2 is an integer".

If I assume the above, answer is B.
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 [#permalink] New post 31 May 2006, 21:31
i agree if indeed st 1 is n^2 is an integer

then answer is B
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 [#permalink] New post 01 Jun 2006, 13:30
Sorry. I corrected my post to read: "n^2 is an integer".

If n^2 is an integer, shouldn't n be an integer. Does the rule follow that an if n^2 is an integer, n must also be an integer?
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 [#permalink] New post 01 Jun 2006, 14:28
(B) as well

from (1)
if n^2 = 10, n^2 is integer but n is not
if n^2 = 4, n^2 is integer but n could be 2 or -2

Not Sufficient

(2) sqrt(n) = k with k integer
Thus n = k^2 which means n is an integer

Sufficient
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 [#permalink] New post 02 Jun 2006, 19:34
A is not true since n can sqrt of n...

B will always produce n as integer.
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Re: DS-OG #146 [#permalink] New post 03 Jun 2006, 04:33
buckkitty wrote:
Is n an integer?

1) n^2 is an integer
2)SQRT(n) is an integer


Please give explanations with answer. thanks


Case1: n^2 is an integer

Let's say n= (1.25) ^ 1/2
So n^2 = 1.25 which is not an integer.

Case2: n^1/2 is an integer

Let's say n^1/2 = x which is an integer.
So n = x^2 which should be an integer.

So St2 is sufficient.

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 [#permalink] New post 03 Jun 2006, 06:02
it is an yes/no data suuiciency.we shud b able to say yes/no for the question asked using the given data.here we shud say whether n is an integer or not...

start with AD/BCE

i)it says n^2 is an integer
16 is an integer.sqrt(16) ie n=4.which is also integer.
therefore we can say YES.
consider 2 is an integer.2^(1/2) is not integer but (2^(1/2)) is an integer
therefore we can say NO.
when 4 the same stem we get both answers YES ans also NO..
we can say the stmt is not sufficient.

therfore A and D goes out.
now we r left with B.

ii)it says n^(1/2) is an integer which straightly gives us tht n is an integer.
eg:n=16,1,2,9............

hence,b is suff
giving us answer B
  [#permalink] 03 Jun 2006, 06:02
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