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Is N divisible by 7?

(1) N = x-y, where x and y are integers (2) x is divisible by 7, and y is not divisible by 7

Hi guys, my question is not in regards to how to solve this problem, but how to know if the answer is required to be an integer or not? For example, the question above does not mention any requirements for the answer to be an integer, yet that is exactly what the outcome requires. Any help would be greatly appreciated.

(1) N = x-y, where x and y are integers (2) x is divisible by 7, and y is not divisible by 7

Hi guys, my question is not in regards to how to solve this problem, but how to know if the answer is required to be an integer or not? For example, the question above does not mention any requirements for the answer to be an integer, yet that is exactly what the outcome requires. Any help would be greatly appreciated.

Thanks

N to be divisible by 7, it MUST be an integer (at least on the GMAT) because the question makes no sense if N is not an integer. On the GMAT divisibility is applied only to the integers.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that: 1. \(a\) is an integer; 2. \(b\) is an integer; 3. \(\frac{a}{b}=integer\).

As for the question: Is N divisible by 7?

(1) N = x-y, where x and y are integers. Clearly insufficient. (2) x is divisible by 7, and y is not divisible by 7. Clearly insufficient.

(1)+(2) N={multiple of 7}-{not a multiple of 7}={not a multiple of 7}. Sufficient.

Answer: C.

Below might help to understand this concept better.

If integers \(a\) and \(b\) are both multiples of some integer \(k>1\) (divisible by \(k\)), then their sum and difference will also be a multiple of \(k\) (divisible by \(k\)): Example: \(a=6\) and \(b=9\), both divisible by 3 ---> \(a+b=15\) and \(a-b=-3\), again both divisible by 3.

If out of integers \(a\) and \(b\) one is a multiple of some integer \(k>1\) and another is not, then their sum and difference will NOT be a multiple of \(k\) (divisible by \(k\)): Example: \(a=6\), divisible by 3 and \(b=5\), not divisible by 3 ---> \(a+b=11\) and \(a-b=1\), neither is divisible by 3.

If integers \(a\) and \(b\) both are NOT multiples of some integer \(k>1\) (divisible by \(k\)), then their sum and difference may or may not be a multiple of \(k\) (divisible by \(k\)): Example: \(a=5\) and \(b=4\), neither is divisible by 3 ---> \(a+b=9\), is divisible by 3 and \(a-b=1\), is not divisible by 3; OR: \(a=6\) and \(b=3\), neither is divisible by 5 ---> \(a+b=9\) and \(a-b=3\), neither is divisible by 5; OR: \(a=2\) and \(b=2\), neither is divisible by 4 ---> \(a+b=4\) and \(a-b=0\), both are divisible by 4.

(1) N = x-y, where x and y are integers (2) x is divisible by 7, and y is not divisible by 7

Hi guys, my question is not in regards to how to solve this problem, but how to know if the answer is required to be an integer or not? For example, the question above does not mention any requirements for the answer to be an integer, yet that is exactly what the outcome requires. Any help would be greatly appreciated.

Thanks

One more thing: every GMAT divisibility question will tell you in advance that any unknowns represent positive integers.

So, if it were realistic GMAT question it would most probably ask: If N is an integer, is N divisible by 7? _________________

Thank you for all the information, it was very helpful, I was just unclear previously because when I read the question "Is N divisible by 7" I looked at it as: 1/7 is possible, but will be a decimal. With no other information stating it is required to be an integer I felt it was an acceptable answer. I was just unsure if I had missed some information or have not been looking at the question appropriately.

Statement 1: N = x-y where x and y are integers. Clearly, the difference of two integers can be any other integer, and some integers are divisible by 7 while others are not. Insufficient.

Statement 2: x and y are not defined. Insufficient.

Combining both statements, N = x - y where x is divisible by 7 and y is not divisible by 7 = multiple of 7 - (non multiple of 7) = not divisible by 7 Sufficient.

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

If any 2 integers are divisible by a number , then sum and subtraction of the integers should also be divisible by the number . For Ex:- if x and y both are factors of 2, then x-y and x+y will also be factors of 2 .

If any 2 integers are divisible by a number , then sum and subtraction of the integers should also be divisible by the number . For Ex:- if x and y both are factors of 2, then x-y and x+y will also be factors of 2 .

Experts please reply .

Yes, say the common factor is x.

So the numbers are ax and bx.

Sum = ax + bx = x (a + b) => divisible by x Difference = ax - bx = x(a - b) => divisible by x (assuming a > b. If b is greater, then difference will be bx - ax)

What about '0' as the value of 'y'? 'N' should still be divisible by 7.

Many thanks in advance.

ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

(2) x is divisible by 7, and y is not divisible by 7 --> NOT SUFFICIENT

(1) + (2) --> SUFFICIENT; if x is divisible by 7, then x is a multiple of 7. Likewise, using the same reasoning, y is not a multiple of 7. x+y is therefore not a combination of multiples of 7 and is not divisible by 7

gmatclubot

Re: Is N divisible by 7?
[#permalink]
28 Sep 2016, 12:21

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