alexBLR wrote:
This is the question from GMAT Quant Review:
If x is a positive integer , is \sqrt{x} an integer?
1) \sqrt{4x} is an integer.
2) \sqrt{3x} is not an integer.
My logic to solve this question:
\sqrt{4x}=2*\sqrt{x}, so \sqrt{x} can either be integer or not an integer (for example \sqrt{x}=2.5) and the 2*\sqrt{x} is still an integer. So Statement 1 is insufficient.
\sqrt{3x}= \sqrt{3}*\sqrt{x}. As \sqrt{3} is not an integer, the \sqrt{x} can be either integer or non integer and the \sqrt{3}*\sqrt{x} will still be not integer. So Statement 2 is insufficient.
S1 and S2 together is still insufficient as \sqrt{x}=2 and \sqrt{x}=2.5 both satisfy statements requirement.
So I choose E as an answer.
Is there a flaw in my reasoning?
OG Quant review answer to this question is different from E.
Please advice.
IMO D...
Ques: if x is a positive integer, is
\sqrt{x} an integer?
S1:
\sqrt{4x} is an integer
-->
2* \sqrt{x} is an integer -->
\sqrt{x} has to be an integer.. as x is a positive integer and hence cannot be a fraction. Therefore SUFF
S2:
\sqrt{3x} is an integer
-->
\sqrt{3}*\sqrt{x} -->
\sqrt{x} is not an integer as same could be a of a form of
a\sqrt{3} where 'a' is a positive integer. Therefore SUFF
_________________
Cheers!
JT...........
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