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# IS p < 0? 1) p + 6 < |p| 2) p^2 - p > p^2 Thanks

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IS p < 0? 1) p + 6 < |p| 2) p^2 - p > p^2 Thanks [#permalink]  27 Sep 2004, 18:41
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IS p < 0?

1) p + 6 < |p|

2) p^2 - p > p^2

Thanks.
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Joined: 15 Dec 2003
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[#permalink]  27 Sep 2004, 18:55
D for me
1) you cannot have a positive number + a positive integer being larger than the abs val of the same number. p must be negative
2) you can find out by logic or working out the inequality
p - p^2 < -(p^2)
p<0
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Paul

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[#permalink]  27 Sep 2004, 19:36
Yes the answer is D. I made a very stupid mistake in my calculations.
[#permalink] 27 Sep 2004, 19:36
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# IS p < 0? 1) p + 6 < |p| 2) p^2 - p > p^2 Thanks

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