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Is p>q? 1. 1/p<1/q 2. p/q>.25

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Manager
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Is p>q? 1. 1/p<1/q 2. p/q>.25 [#permalink] New post 01 Aug 2005, 07:53
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is p>q?

1. 1/p<1/q

2. p/q>.25
Senior Manager
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 [#permalink] New post 01 Aug 2005, 09:23
quick E.
if it isn't, than it is very tricky question.
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 [#permalink] New post 01 Aug 2005, 10:12
Another one for E.

stmt 1 is out becuase p and q may or may not be integers so depending on whether p and q are integers or not.

stmt 2 is insufficient because it say P/q > 25/100 so again, this is true or false depending on the value of P and Q
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 [#permalink] New post 01 Aug 2005, 13:22
C

Is p>q?


1. 1/p<1/q

2. p/q>.25 => p and q are either both < 0 or both > 0


when both < 0, if (1) is true, then 1/|p| > 1/|q| => |p| < |q| => p > q

when both > 0, if (1) is true, then |p| > |q| => p > q
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Re: DS-integers,, [#permalink] New post 01 Aug 2005, 13:46
Dan wrote:
Is p>q?

1. 1/p<1/q

2. p/q>.25


My answer is C

Condition 1
Multiply by pq on both sides gives

q<p if pq is positive (both + or both -)

q>p if pq is negative (if one of them is negative)

Condition 2

p>0.25q (if q is +)
p<0.25q (if q is -)

Combine both condition

Condition 1 can be interpreted as p/q>1 if q is positive and p/q<1 if q is negative but combinin with condition 2 q is positive, then p is also postive for p/q to be > 0.25

For all positive values of p and q, p>q for both condition to be satisfied...
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Fear Mediocrity, Respect Ignorance

Re: DS-integers,,   [#permalink] 01 Aug 2005, 13:46
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Is p>q? 1. 1/p<1/q 2. p/q>.25

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