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Is p + q > pq ? (1) p > 0 > q (2) |q| = p

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Bunuel
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Is p + q > pq ? (1) p > 0 > q (2) |q| = p [#permalink] New post   25 May 2022, 06:44
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A
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E

Difficulty:

65% (hard)

Question Stats:

56% (02:17) correct 44% (02:03) wrong based on 88 sessions
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Is p + q > pq ?

(1) p > 0 > q

(2) |q| = p

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prithviraj99
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Re: Is p + q > pq ? (1) p > 0 > q (2) |q| = p [#permalink] New post   25 May 2022, 06:58
Imo answer is C

1)p>0>q => q<0<p
Meaning q is -ve number and p is a +ve number

p+q>pq can't be concluded with this information. Insufficient

2)|q|=p
q=+p or -p

q=+p
2p>p^2 need not be true for all p . Eg p=2

q=-p

0>-p^2 This is valid but since statement 2 alone is not fully sufficient.

Let's see if we can achieve sufficiency by considering both the statement

If q is -ve and p is +ve and |q|=p meaning q = -p

We have the valid case of -p^2 <0

So together both statements are sufficient

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VaibhavSarda
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Re: Is p + q > pq ? (1) p > 0 > q (2) |q| = p [#permalink] New post   04 Jun 2022, 03:30
Bunuel wrote:
Is p + q > pq ?

(1) p > 0 > q

(2) |q| = p


Any example to prove statement 1 alone is insufficient?
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hardikpujara
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Re: Is p + q > pq ? (1) p > 0 > q (2) |q| = p [#permalink] New post   02 Jul 2022, 11:13
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VaibhavSarda wrote:
Bunuel wrote:
Is p + q > pq ?

(1) p > 0 > q

(2) |q| = p


Any example to prove statement 1 alone is insufficient?


Assume p=5, q=-4, p+q>pq
Assume p=1/2, q=-1 , p+q=pq

Hence statement A alone is insufficient.
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Re: Is p + q > pq ? (1) p > 0 > q (2) |q| = p [#permalink]
02 Jul 2022, 11:13
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Bunuel
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