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Is p+q >r+s 1.p>r+s 2.q>r+s

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Director
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Is p+q >r+s 1.p>r+s 2.q>r+s [#permalink] New post 07 Sep 2004, 13:01
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:00) wrong based on 2 sessions
Is p+q >r+s
1.p>r+s
2.q>r+s
Manager
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 [#permalink] New post 07 Sep 2004, 13:13
I think the answer is C.

st.1
p > r+s
r+s = 2 than p > 2, but we still don´t know the value of q.

st.2
q > r+s
r+s = 2 than q > 2, but we still don´t know the value of p.

Both statements together prove that p and q are more than r+s.

Please correct me if I am wrong.

Regards,

Alex
Director
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Re: DS Greater than [#permalink] New post 07 Sep 2004, 15:17
saurya_s wrote:
Is p+q >r+s
1.p>r+s
2.q>r+s


Got C
either one or 2 is not sufficient if we plu in -ve nums for pqrs
Intern
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 [#permalink] New post 15 Sep 2004, 15:06
Answer should be E.

first and second statements insufficient.

Togther
let r+s = -10
p = -6
q = -6

p+q not greater than r+s gives a No answer, but we can easily pick numbers to get an Yes answer.

So, E.
Senior Manager
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 [#permalink] New post 15 Sep 2004, 18:00
What a beauty scoobee. Yes E IT SHUD BE.
Manager
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 [#permalink] New post 16 Sep 2004, 04:13
Very nice indeed Scooby.

Regards,

Alex
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 [#permalink] New post 16 Sep 2004, 06:21
(1)+(2) => p+q > 2(r+s)
question is "is 2(r+s) > r+s ?"
Yes if r+s >0
No if <0
  [#permalink] 16 Sep 2004, 06:21
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