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# Is r > s ?

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Author Message
TAGS:
Manager
Joined: 17 Nov 2009
Posts: 239
Followers: 1

Kudos [?]: 20 [0], given: 17

Is r > s ? [#permalink]  01 Oct 2010, 07:58
00:00

Difficulty:

25% (medium)

Question Stats:

82% (01:36) correct 18% (00:37) wrong based on 44 sessions
Is r > s ?

(1) -r + s < 0
(2) r < | s |
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 31356
Followers: 5367

Kudos [?]: 62595 [1] , given: 9457

Re: Is r>s? [#permalink]  01 Oct 2010, 08:03
1
KUDOS
Expert's post
agnok wrote:
Is r > s ?

(1) -r + s < 0
(2) r < | s |

Is $$r>s$$?

(1) $$-r+s<0$$ --> add $$r$$ to both parts --> $$s<r$$, directly answers the question. Sufficient.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.

_________________
Manager
Joined: 06 Nov 2009
Posts: 177
Concentration: Finance, Strategy
Followers: 1

Kudos [?]: 8 [0], given: 3

Re: Is r>s? [#permalink]  01 Oct 2010, 08:25
Answer A is correct, try to solve such problems by number plug-in
Re: Is r>s?   [#permalink] 01 Oct 2010, 08:25
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# Is r > s ?

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