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# Is r > s ?

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Manager
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Is r > s ? [#permalink]

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01 Oct 2010, 08:58
1
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Difficulty:

5% (low)

Question Stats:

80% (01:39) correct 20% (00:39) wrong based on 152 sessions

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Is r > s ?

(1) -r + s < 0
(2) r < | s |
[Reveal] Spoiler: OA
Math Expert
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Kudos [?]: 85312 [1] , given: 10236

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01 Oct 2010, 09:03
1
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Expert's post
agnok wrote:
Is r > s ?

(1) -r + s < 0
(2) r < | s |

Is $$r>s$$?

(1) $$-r+s<0$$ --> add $$r$$ to both parts --> $$s<r$$, directly answers the question. Sufficient.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.

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01 Oct 2010, 09:25
Answer A is correct, try to solve such problems by number plug-in
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Re: Is r > s ? [#permalink]

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13 Mar 2016, 06:57
HERE statement 1 is sufficient as we directly arrive at the result of r>s

statement 2 is insufficient as it tells us => s>r or s<-r => not sufficient
hence A is sufficient
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Re: Is r > s ? [#permalink]

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18 Jul 2016, 01:41
agnok wrote:
Is r > s ?

(1) -r + s < 0
(2) r < | s |

This is a yes or no question. Any value as long as it is definite yes or definite no will be correct
Is r > s ?
(1) -r + s < 0
r>s
Is r > s = YES
SUFFICIENT

(2) r < | s |
r<s or r<-s

First case
r<s
Is r > s NO

Second case
r <- s sometimes yes, sometimes no

Is 4 < -5 no
Is 4 < -(-5) yes

INSUFFICIENT

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Re: Is r > s ? [#permalink]

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24 Jul 2016, 06:49
2) r < |s|
doesn't it mean that r lies between s and -s -s < r < s ... so r definitely is smaller than s ?
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Re: Is r > s ? [#permalink]

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24 Jul 2016, 08:02
Expert's post
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thapliya wrote:
2) r < |s|
doesn't it mean that r lies between s and -s -s < r < s ... so r definitely is smaller than s ?

That's not correct.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.
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Re: Is r > s ?   [#permalink] 24 Jul 2016, 08:02
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