goalsnr wrote:

ventivish wrote:

Hi I agree with stat B

Stat1. Both x=2 and x=4 give a YES for the question but 5 gives a NO.So insifficient

Stat2. For all values of x<0 ; sqrt[(x-3)^2] is not equal to (3-x)^2 . So sufficient.

I think the trick is to plug in numbers

My question is why the solving for x will not work?

You need to be careful with solving for variables.

If you solve for sqrt[(x-3)^2]=(3-x)^2

your calculations assume that (x-3) is positive, it could be that x-3 is negative in which case your equation would look like this:

-(x-3)=(3-x)^2

This would solve for x=2 and x=3

So you still have 2 options, x=2 and x=4 which is insufficient.

If you tried plugging in numbers you would just save time.

Hope this helps!