Is sqrt.(x-3)^2 = 3-x?
(1) x != 3
(2) -x|x| > 0
Looking for explanations for both the statements here.
According to me statement 1 is sufficient as it yields NO
hmmm. skipped A b/c when i looked at it I wasn't sure so I went to B.
B tells me that x has to be a negative number |x| is always going to be positive. but if -x|x|>0 then x must be a negative number. lets say x=2
-(2)|2| >0??? no... so it must be negative x=-2: -(-2)|x|>0 x =4
now it can easily be seen that the answer (When using stmnt 2) is NO.
ex: (-2-3)^2=3-2... NO
Stmnt 1: now going back to this I understand it better. x!=3. This is not saying that x=3. So we have no idea and thus stmnt 1 is insuff.