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is my understanding correct ? 1) possibilities of sets with 6 highest number are [1,2,3,4,6], [1,2,4,5,6], [2,3,4,5,6] ... Thus sufficient.... 2) 2 being the lowest element in set, the possibility of the sets are numerous but Avg will be always greater than Mean. e.g [2,3,4,6,100] or [2,4,5,6,1000] in all cases Avg will greater than Mean, thus sufficient. So answer is D.....

Re: Is the average of a set of 5 distinct positive integers {a, b, 4, 6, 2 [#permalink]

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28 Sep 2011, 09:34

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shrive555 wrote:

Is the average of a set of 5 distinct positive integers { a , b , 4, 6, 2} greater than the median? 1. the highest number in the set is 6 2. the lowest number in the set is 2

statement 1 -the highest number in the set is 6

1 possible set can be (1,2,3,4,6) Then avg =3.2 and median 3 , so avg > median . Another set can be (2,3,4,5,6) then avg =4 and median 4, so avg =median so statement 1 insufficient.

statement 2 -the lowest number in the set is 2 1possible set can be (2,3,4,5,6) then avg =4 and median 4, so avg =median Another possible set can be (2,3,4,6,10) avg =6 and median 4 , so avg > median so statement 2 insufficient.

combining 2 statements, only set possible is (2,3,4,5,6). avg = median. we get a definite answer 'No' average is not greater than median. Answer C.

Re: Is the average of a set of 5 distinct positive integers {a, b, 4, 6, 2 [#permalink]

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28 Sep 2011, 09:55

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Hey, here's how I would answer this question. I'm going to try and write it out as clearly as I can. Minus the explanation this can be solved well within 2 minutes.

1. Highest number in the set is 6

Since they're all integers and distinct, the mean will be highest when a and b equal 3 & 5 (or vice versa, doesn't matter).

=> {2,3,4,5,6} Mean = 4 Median = 4

Mean will be at its lowest when a & b equal 1 & 3.

=> {1,2,3,4,6} Mean = 3.2 Median = 3

This is all we need to know to conclude that the first statement is INSUFFICIENT. In the first case the mean is not greater than the median, but in the second case it is.

2. The lowest number in the set is 2

Since the numbers are positive and there is now no upper limit on the integers, it is important to first find the lowest possible value of the mean since adding 300 or any huge number will ensure that the mean is greater than the median.

a & b equal 3 & 5

=> {2,3,4,5,6} Mean = 4, Median = 4.

Again we have a case where the mean is not greater and one where it is (i.e. adding a huge number to the set). INSUFFICIENT.

Combining the two we know that 2 is the lowest number and 6 is the highest, and from our calculations it is clear that while the mean can equal the median, it CAN NOT be greater.

Re: Is the average of a set of 5 distinct positive integers {a, b, 4, 6, 2 [#permalink]

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13 Sep 2016, 03:12

I have a question w.r.t Statement 2. Can we get a 'Yes' case. The cases that I can see in the official solution and the ones that are posted here produce a 'No' in case of Statement 2 (precisely Mean is not greater than Median, and Mean=Median) I cannot locate a case where Mean > Median and I believe that probably can make Statement 2 sufficient.

Bunuel - I would like to understand where am I going wrong or may be there is an altered version of this question that's present in the database?

I have a question w.r.t Statement 2. Can we get a 'Yes' case. The cases that I can see in the official solution and the ones that are posted here produce a 'No' in case of Statement 2 (precisely Mean is not greater than Median, and Mean=Median) I cannot locate a case where Mean > Median and I believe that probably can make Statement 2 sufficient.

Bunuel - I would like to understand where am I going wrong or may be there is an altered version of this question that's present in the database?

Thank You in advance

The average of {2, 4, 6, 100, 200}, which is ~62, is greater than the median of {2, 4, 6, 100, 200}, which is 6.
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