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Is the average of r, s, and t greater than the average of m,

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New post 06 May 2006, 04:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is the average of r, s, and t greater than the average of m, n, and p?

1) The median of r, s, and t is greater than that of m, n, and p
2) r>m, s>n, t>p
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New post 06 May 2006, 05:05
Ans B

to satisfy the condisiton r +s +t > m+n+p

A -- lots of possiblity

B r +s +t will always be greater than m + n + p
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New post 06 May 2006, 05:17
The answer should be B
1) if you take the first statement as true, this can either lead to the original sentence true/false. let us pick numbers. Let

R 5
S 6
T 7
MEDIAN 6
AVERAGE 6
M 2
N 7
O 6
MEDIAN 7
AVERAGE 5
So here is an example where although the median is greater, the average is still less. There are easy examples available where it can be proved that if the avreage is greater the median is also greater. So we cannot justify the original statement using the first statement alone.

2) Let us take the second statement, if R>M, S>N, T>O, Then definately the average is bound to be greater. Hence we can justify the original statement.

Hence B
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New post 06 May 2006, 11:24
Agree with B :wink:
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New post 07 May 2006, 00:17
question r+s+t > m+n+p

B directly gives this relation!
  [#permalink] 07 May 2006, 00:17
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Is the average of r, s, and t greater than the average of m,

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