chetan2u wrote:
reidoxudo wrote:
Is the integer 2b divisible by 6 ?
(1) 8b is divisible by 3.
(2) 9b is divisible by 12
Hi,
Firstly I am shifting it to correct forum--DS..
now for solution of it--
Info from Q--
1)Is the integer 2b divisible by 6
2) factors of 6 are 2*3 and we already have 2 in numerator.
3) so our Q is to find is to find IF b IS MULTIPLE OF 3?
lets see the statements
(1) 8b is divisible by 3.
since 8b is div by 3, and 8 is not div by 3, so b is div by 3..
Exactly what we are looking for..
Suff
(2) 9b is divisible by 12
in denominator we have 4*3..
since 9 is div by 3 out of 4 and 3..
b will be div by 4, but we cannot say anything about 3..
insuff
ans AHow is this the solution, when in your previous post you just said that statement 1 is not sufficient?
You claimed that if b= 3/2, then statement "(1) 8b is divisible by 3" can still hold true, because 8b = 8(3/2) = 24/2 = 12, and 12 is divisible by 3. However, when you plug it back into the question stem, is "is 2b divisible by 6," then 2b = 2 (3/2) = 3, and 3 is not divisible by 6. However, if b = 3, then 8b = 8(3) = 24, which is divisible by 3, and when you plug is into the question stem, then 2b = 2(3) = 6, which is divisible by 6. Therefore, statement 1 is insufficient.
Statement (2), 9b is divisible by 12, means that b must multiple by 9 so that the products becomes a multiple of 12 (it may equal 12 as well). Note, that it must still result in 2b being an integer as stated in the question stem. So, if b=4, than 9b = 36, and 36 is divisible by 12, and 2b = 2(4) = 8, which is not divisible by 6. However, if b=12, then 9b=108, which is divisible by 12, and when we plug 12 for b in the question stem, 2b=2(12)=24, we find that 24 is divisible by 6. Therefore, statement 2 is insufficient.
When we combine statements, we find that b has to be a number that when it's multiplied by 8, it is divisible by 3, and when it's multiplied by 9, it is divisible by 12. Therefore, b must be a common multiple for 3 & 12.
b = 12, 24, 36, 48, etc..
If any of those value for b are multiplied by 2, then 2b is divisible by 6.
Therefore, both statement 1&2 are required for sufficiency.
Answer is C.
*please kudos"