Is the integer m an even number? : GMAT Data Sufficiency (DS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 20 Jan 2017, 17:40

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is the integer m an even number?

Author Message
TAGS:

### Hide Tags

Manager
Joined: 25 Jun 2012
Posts: 65
Followers: 0

Kudos [?]: 48 [0], given: 21

Is the integer m an even number? [#permalink]

### Show Tags

15 Nov 2012, 11:03
6
This post was
BOOKMARKED
00:00

Difficulty:

35% (medium)

Question Stats:

63% (03:03) correct 37% (00:48) wrong based on 311 sessions

### HideShow timer Statistics

Is the integer m an even number?

(1) |m| = -m

(2) (m)(m - 1)(m + 2) = 0
[Reveal] Spoiler: OA
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Posts: 3706
Followers: 1296

Kudos [?]: 5846 [3] , given: 66

Re: Is the integer m an even number? [#permalink]

### Show Tags

15 Nov 2012, 15:07
3
KUDOS
Expert's post
1
This post was
BOOKMARKED
Is the integer m an even number?
(1) |m| = -m
(2) (m)(m - 1)(m + 2) = 0

I'm happy to help with this.

Statement #1 is equivalent to the statement that m =< 0, that m is zero or a negative number. For more explanation of this, see this blog post:
http://magoosh.com/gmat/2012/gmat-math- ... -of-minus/
We know from this that m is zero or negative, but not necessarily even or odd, so this statement, alone and by itself, is not sufficient.

Statement #2: We solve this with the Zero Product Property.
The ZPP says:
If A*B = 0, then A = 0 or B = 0
Notice that, in this statement, the word "or" is no garnish, but rather an essential piece of mathematical equipment.
By extension,
If A*B*C = 0, then A = 0 or B = 0 or C = 0.

Here, we have:
(m)(m - 1)(m + 2) = 0 ===> m = 0 OR (m - 1) = 0 OR (m + 2) = 0
===> m = 0 OR m = +1 or m = -2
From this statement, m could be any of these three, so it could be even or odd. This statement, alone and by itself, is not sufficient.

Combined statements
We look at our set from the second statement, m = {0, +1, -2}, and because of the constraint of the first statement, we know m must be zero or negative, so we can keep 0 and -2, but we have to exclude +1. Now we are down to m = {0, -2}. We don't know which one m equals, but since both of them are even, we now definitively know that m is even. Thus, combined, the statements are sufficient.

Does all this make sense?
Mike
_________________

Mike McGarry
Magoosh Test Prep

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13468
Followers: 575

Kudos [?]: 163 [0], given: 0

Re: Is the integer m an even number? [#permalink]

### Show Tags

15 May 2014, 01:37
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Director
Joined: 25 Apr 2012
Posts: 728
Location: India
GPA: 3.21
Followers: 43

Kudos [?]: 698 [0], given: 723

Re: Is the integer m an even number? [#permalink]

### Show Tags

15 May 2014, 02:18
Is the integer m an even number?

(1) |m| = -m

(2) (m)(m - 1)(m + 2) = 0

Sol: Given in St 1 |m|=-m or $$m+|m|=0$$ ----->this implies some a positive no + m= 0 and therefore m has to be a negative number.

Now m can be -2 then ans is Y but if m=-3 then no

So Option A and D are ruled out

St 2 tells you that possible values of m are 0,1 and -2
Again if m=0,-2 then m is even number but if m=1 then m is odd. Option B ruled out

Combining we get that m is a negative number so m=-2. Ans is C
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Manager
Joined: 07 May 2013
Posts: 109
Followers: 0

Kudos [?]: 24 [0], given: 1

Re: Is the integer m an even number? [#permalink]

### Show Tags

06 Jun 2014, 19:07
Great explanation mike. I solved the problem but without understanding the importance of OR. Good job and please keep us enlightened
Manager
Joined: 20 Dec 2013
Posts: 127
Followers: 10

Kudos [?]: 93 [0], given: 1

Re: Is the integer m an even number? [#permalink]

### Show Tags

06 Jun 2014, 23:31
Is the integer m an even number?

(1) |m| = -m

(2) (m)(m - 1)(m + 2) = 0

Statement I is insufficient:

m = 0, m = -1 would be suffice the statement and m can be even or odd. M can be any negative number or zero

Statement II is insufficient:

Either m = 0 OR m = 1 OR m = -2

Combining:

m = 0 or m = -2 which states that m will be even

_________________

76000 Subscribers, 7 million minutes of learning delivered and 5.6 million video views

Perfect Scores
http://perfectscores.org

Manager
Joined: 04 Jan 2014
Posts: 129
Followers: 1

Kudos [?]: 10 [0], given: 24

Re: Is the integer m an even number? [#permalink]

### Show Tags

18 Jun 2014, 01:00
Is zero considered an even integer?
Math Expert
Joined: 02 Sep 2009
Posts: 36583
Followers: 7087

Kudos [?]: 93281 [1] , given: 10555

Re: Is the integer m an even number? [#permalink]

### Show Tags

18 Jun 2014, 01:02
1
KUDOS
Expert's post
1
This post was
BOOKMARKED
pretzel wrote:
Is zero considered an even integer?

ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself, (or, which is the same, zero is a multiple of every integer except zero itself).

Check more here: tips-and-hints-for-specific-quant-topics-with-examples-172096.html#p1371030

Hope it helps.
_________________
Manager
Joined: 04 Jan 2014
Posts: 129
Followers: 1

Kudos [?]: 10 [0], given: 24

Re: Is the integer m an even number? [#permalink]

### Show Tags

18 Jun 2014, 01:04
Thank Bunnel for your prompt reply! I chose E because I narrowed down to 0 and 2 from the 2nd statement.
Math Expert
Joined: 02 Sep 2009
Posts: 36583
Followers: 7087

Kudos [?]: 93281 [0], given: 10555

Re: Is the integer m an even number? [#permalink]

### Show Tags

18 Jun 2014, 01:29
pretzel wrote:
Thank Bunnel for your prompt reply! I chose E because I narrowed down to 0 and 2 from the 2nd statement.

If from (2) we had that m is either 0 or 2, then the answer would be B. Because both 0 and 2 are even. But from (2) m is 0, 1, or -2. If m is 0 or -2, then the answer to the question is YES but if m is 1, then the answer to the question is NO. So, (2) is not sufficient.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13468
Followers: 575

Kudos [?]: 163 [0], given: 0

Re: Is the integer m an even number? [#permalink]

### Show Tags

23 Jun 2015, 05:39
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13468
Followers: 575

Kudos [?]: 163 [0], given: 0

Re: Is the integer m an even number? [#permalink]

### Show Tags

10 Aug 2016, 05:37
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Intern
Joined: 23 Jan 2015
Posts: 43
Location: India
Concentration: Operations
WE: Information Technology (Computer Software)
Followers: 1

Kudos [?]: 4 [0], given: 76

Re: Is the integer m an even number? [#permalink]

### Show Tags

12 Aug 2016, 20:15
Is the integer m an even number?

(1) |m| = -m

(2) (m)(m - 1)(m + 2) = 0

From statement 1, we know LHS has absolute value.
Since absolute value can never be negative, so the only plausible solution was 0

I am sure am missing out something- can anyone help me out?
Math Expert
Joined: 02 Sep 2009
Posts: 36583
Followers: 7087

Kudos [?]: 93281 [1] , given: 10555

Re: Is the integer m an even number? [#permalink]

### Show Tags

12 Aug 2016, 23:51
1
KUDOS
Expert's post
Anigr16 wrote:
Is the integer m an even number?

(1) |m| = -m

(2) (m)(m - 1)(m + 2) = 0

From statement 1, we know LHS has absolute value.
Since absolute value can never be negative, so the only plausible solution was 0

I am sure am missing out something- can anyone help me out?

This is explained above: from (1) $$-m\geq 0$$ --> $$m \leq 0$$ --> m can be any non-positive value to satisfy |m| = -m.
_________________
Re: Is the integer m an even number?   [#permalink] 12 Aug 2016, 23:51
Similar topics Replies Last post
Similar
Topics:
If n and m are positive integers, is n + m even? 1 06 Dec 2016, 06:09
7 Is the positive integer x an even number? 6 07 Oct 2015, 05:23
9 Is the product of integers M and N even? 12 09 Apr 2015, 05:04
3 If a and b are integers, and m is an even integer, is ab/4 5 19 Dec 2012, 22:45
2 If M and N are positive integers, then is M an even integer? 4 09 Feb 2012, 16:57
Display posts from previous: Sort by