Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Statement 1 gives possible values of x as -3, 0 3, 6, 9 .. out of which ... -6, 0, 6, 12 ... are the ones divisible by 6, others are not. Statement 2 gives possible values of x as ...-4 , -2, 0, 2, 4, 6 out of which 0, 6, 12 .. are divisible by 6, others are not.

Taken together, the values 0, 6, 12 satisfy both statements and are all divisible by 6, so the answer is "Yes" and i would choose option C.

Ans is C. Here is another way of solving the problem.

Question asked is IS x divisible by 6 means we need to prove that x is divisible by 2 and also x is divisible by 6. (Divisibility rule for 6)

Clue 1 - X + 3 is divisible by 3 ==> One rule is If two numbers are multiple of a number, then the sum of the two numbers is also multiple of that number. Here it is said that x + 3 is divisible by 3 in other words, x + 3 is a multiple of 3. Of the two numbers, 3 is multiple of 3 and also x should be multiple of 3 to satisfy the condition that x + 3 is a multiple of 3. This concludes that x is divisible by 3. One part of the divisibility rule is satisfied. But we don't know anything whether x is divisible by 2 or not.

Clue 2 - x + 3 is Odd. The sum of two numbers is odd only when both the numbers one is odd and the other is even. Here 3 is already odd, so x should be even in other words, x is divisible by 2. But we don't know if still x is divisible by 3.

Now combining Clue 1 and 2, x is even and is divisible by 3. Hence both clues are needed to solve the problem.

Is the integer x divisible by 6? (1) x + 3 is divisible by 3 (2) x + 3 is an odd number.

Answer choices: (a) Statement 1 alone is sufficient, but Statement 2 alone is not sufficient. (b) Statement 2 alone is sufficient, but Statement 1 alone is not sufficient. (c) Either statements are NOT sufficient, but BOTH together are sufficient. (d) Each statement ALONE is sufficient. (e) Neither statement Alone is sufficient.

(1) x+3/ 3 = k (integer) x/3+1=k --> x is multiple of 3 not sufficient (2)x + 3 is an odd number -->.. x must be even integer. not sufficient combine ( x=6k..

C _________________

Your attitude determines your altitude Smiling wins more friends than frowning

to be x divisible by 6, it should be divisible by 2 and 3

Statement 1 says that X+3 is divisible by 3, it means both x and 3 are divisible by 3 , but we dont know if x is divisible by 2. so this statement is not sufficient.

Statement 2 says that x+3 is odd. It means x is an even number which is divisible by 2(because even+odd can only give odd value). but here we dont know if x is divisible by 3. So this statement is not sufficient.

now consider both the statements together we can say that x is divisible by 6,Statement 1 says that x is divisible by 3 and statement 2 says that x is divisible by 2. Thats what we wanted to know.

(1) x + 3 is divisible by 3. This basically means that x is divisible by 3 (x = {a multiple of 3} - 3 = {a multiple of 3}), which is not sufficient to say whether it's divisible by 6.

(2) x + 3 is an odd number. This means that x is even (\(x=odd-3=odd-odd=even\)). Not sufficient.

(1)+(2) x is an even multiple of 3, hence it's a multiple of 6. Sufficient.

So, my final tally is in. I applied to three b schools in total this season: INSEAD – admitted MIT Sloan – admitted Wharton – waitlisted and dinged No...

HBS alum talks about effective altruism and founding and ultimately closing MBAs Across America at TED: Casey Gerald speaks at TED2016 – Dream, February 15-19, 2016, Vancouver Convention Center...