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# is the intersection of two lines x + y = 8 and 4y - 4x=16

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is the intersection of two lines x + y = 8 and 4y - 4x=16 [#permalink]  17 Feb 2013, 20:55
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Question Stats:

40% (02:04) correct 60% (01:12) wrong based on 0 sessions
Is the intersection of two lines x + y = 8 and 4y - 4x=16 inside the circle: x^2 + y^2 = r^2

(1) r = 81
(2) The center of the circle is at the coordinate (-99,-99)

I doubt on OA , plz explain if you've got the right answer.
[Reveal] Spoiler: OA

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Re: is the intersection of two lines x + y = 8 and 4y - 4x=16 [#permalink]  17 Feb 2013, 21:48
daviesj wrote:
Is the intersection of two lines x + y = 8 and 4y - 4x=16 inside the circle: x^2 + y^2 = r^2

1. r = 81

2. The center of the circle is at the coordinate (-99,-99)

I doubt on OA , plz explain if you've got the right answer.

We ahve two known lines and hence we can find the point of intersection. We need to find whether that point of intersection falls within a circle with centre at the origin and radius "r".

1) Radius can be found and hence circle can be plotted and whether the point falls within the circle or not can be determined. Sufficient.

2) I doubt this statement as it is contradictory to both the question statement and statement 1.
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Re: is the intersection of two lines x + y = 8 and 4y - 4x=16 [#permalink]  18 Feb 2013, 00:43
How can the given circle have its center at (-99,-99)?

The second fact statement can not be right.
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Re: is the intersection of two lines x + y = 8 and 4y - 4x=16 [#permalink]  05 Mar 2013, 18:39
If we know the radius and center , then we can determine whether a point lies in the circle or not.

By question statement it seems that center is at 0,0 if x and y are actual coordinates not the shifted ones

Option B changes the question statement by shifting the coordinates 99 down and left and tells nothing about radius - so not sufficient.
Re: is the intersection of two lines x + y = 8 and 4y - 4x=16   [#permalink] 05 Mar 2013, 18:39
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