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# Is the number of members of Club X greater than the number

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Manager
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Is the number of members of Club X greater than the number [#permalink]

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05 Aug 2006, 08:26
1
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3
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Question Stats:

70% (01:43) correct 30% (00:43) wrong based on 76 sessions

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Is the number of members of Club X greater than the number of members of Club Y ?

(1) Of the members of Club X, 20 percent are also members of Club Y.
(2) Of the members of Club Y, 30 percent are also members of Club X.

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-the-number-of-members-of-club-x-greater-than-the-number-128641.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Aug 2012, 05:25, edited 1 time in total.
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05 Aug 2006, 10:03
E .

There is no mention about the number of members for each club...
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Re: PS-- the members of Club X [#permalink]

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05 Aug 2006, 11:12
ong wrote:
Is the number of members of Club X greater than the number of members of Club Y ?
(1) Of the members of Club X, 20 percent are also members of Club Y.
(2) Of the members of Club Y, 30 percent are also members of Club X.

Stem Is n(x) > n(y)

(1) x=100, y=80(20 from x) -> n(x) > n(y)

or x= 100, y=120(20 from x) --> n(y) > n(x)

Insuff BCE

(2) y=100, x=70(30 are from y) -> n(y) > n(x)
y= 100, x=130(30 are from y) -> n(x) > n(y)

Insuff CE

(1) & (2)
@ this point guessing E

Heman
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05 Aug 2006, 11:39
I'm guessing E. At 20% & 30%, there is no indication for the size relation between the two clubs.
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Re: PS-- the members of Club X [#permalink]

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05 Aug 2006, 13:23
ong wrote:
Is the number of members of Club X greater than the number of members of Club Y ?
(1) Of the members of Club X, 20 percent are also members of Club Y.
(2) Of the members of Club Y, 30 percent are also members of Club X.

let there be Z number of members common to both
hence,
St 1 alone : Insuff.

St 2 alone : Insuff

Together
20% of X = Z = 30 % of Y
X/Y= 3/2 > 1

Hence C
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Re: PS-- the members of Club X [#permalink]

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05 Aug 2006, 14:22
1
KUDOS
n(X)>n(Y)?

S1. n(XnY) = 0.2n(Y) insufficient.
S2. n(XnY) = 0.3n(X) insufficient.

Combine S1 and S2.
0.2n(Y) = 0.3n(X)
n(Y) = 1.5n(X)

n(X) < n(Y) = 1.5n(X) thus sufficient.(n(X) and n(Y) are positive integers)

C it is.
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Re: PS-- the members of Club X [#permalink]

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20 Jul 2011, 09:59
St 1 alone : Insuff.

St 2 alone : Insuff
For C
0.20x = 0.30y
x/y = 30/20 = 1.5 >1
so x>y.
Re: PS-- the members of Club X   [#permalink] 20 Jul 2011, 09:59
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