Is the number y between 0.3 and 0.6 ? : GMAT Data Sufficiency (DS)
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# Is the number y between 0.3 and 0.6 ?

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Is the number y between 0.3 and 0.6 ? [#permalink]

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24 Oct 2013, 16:24
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15% (low)

Question Stats:

84% (01:00) correct 16% (01:46) wrong based on 67 sessions

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Is the number y between 0.3 and 0.6 ?

(1) 640y < 320
(2) 800y > 320

GH-08.07.13 | OE to follow.
[Reveal] Spoiler: OA
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Re: Is the number y between 0.3 and 0.6 ? [#permalink]

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24 Oct 2013, 23:26
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Expert's post
Is the number y between 0.3 and 0.6 ?

Is 0.3 < y < 0.6?

(1) 640y < 320 --> y < 0.5. Not sufficient.

(2) 800y > 320 --> y > 0.4. Not sufficient

(1)+(2) 0.4 < y < 0.5. Sufficient.

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Status: 1,750 Q's attempted and counting
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Re: Is the number y between 0.3 and 0.6 ? [#permalink]

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29 Oct 2013, 21:17
Official Explanation

Statement (1) is insufficient. Simplify the inequality:
640y/640 < 320/640
y < 0.5
y could be between 0.3 and 0.5, but it could also be less than 0.3.

Statment (2) is also insufficient. Again, simplify:
800y/800 > 320/800
y > 0.4
y could be between 0.4 and 0.6, but it could also be greater than 0.6.

Taken together, the statements are sufficient. If y is less than 0.5 and greater than 0.4, it must be between 0.3 and 0.6. Choice (C) is correct.
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Re: Is the number y between 0.3 and 0.6 ? [#permalink]

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27 May 2016, 04:10
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Re: Is the number y between 0.3 and 0.6 ? [#permalink]

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27 May 2016, 04:48
avohden wrote:
Is the number y between 0.3 and 0.6 ?

(1) 640y < 320
(2) 800y > 320

GH-08.07.13 | OE to follow.

Statement 1

640y < 320
y<0.5

Sufficient.

Statement 2

800y > 320

y > $$\frac{32}{80}$$ {$$\frac{32}{80}$$ = $$\frac{4}{10}$$ = 0.4

y > 0.4

y can be 0.41, in which case it lies between 0.3 and 0.6.

y can be 0.61, in which case it does not lie between 0.3 and 0.6.

So statement (2) is not sufficient.

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Re: Is the number y between 0.3 and 0.6 ? [#permalink]

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27 May 2016, 04:56
avohden wrote:
Is the number y between 0.3 and 0.6 ?

(1) 640y < 320
(2) 800y > 320

GH-08.07.13 | OE to follow.

Statement 1

640y < 320
y<0.5

Sufficient.

Statement 2

800y > 320

y > $$\frac{32}{80}$$ {$$\frac{32}{80}$$ = $$\frac{4}{10}$$ = 0.4

y > 0.4

y can be 0.41, in which case it lies between 0.3 and 0.6.

y can be 0.61, in which case it does not lie between 0.3 and 0.6.

So statement (2) is not sufficient.

Hi,

statement I gives you y<0.5...
and Q asked is --- Is the number y between 0.3 and 0.6 ?
if y is 0.4......ans is YES
But if y is 0.2.... ans is NO

so statement I is not sufficient on its own..
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Re: Is the number y between 0.3 and 0.6 ?   [#permalink] 27 May 2016, 04:56
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