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when we combine both statements we get
numbers 12, 24 and so on.
the prime numbers of 4 are 2,2
the prime numbers of 6 are 2.3
therefore 2*2*3 and 2*2*2*3 are also multiples of this numbers.

The key to DS question is to eliminate the answer to a yes or no answer.

2) n is a multiple of six is insufficent.

because N could be 12, 18, 24.

Together are not sufficent because 12 is a multiple of both of 4 and 6 but it's not mutilple of 24. It tells you that N could be or could not be multiple of 24 = insufficient.

Re: is the positive integer n a multiple of 24? [#permalink]
17 Feb 2013, 19:02

buffett76 wrote:

DOES SOMEONE HAVE A GENERAL PROCEDURE TO SOLVE THIS AWFUL QUESTIONS?

is the positive integer n a multiple of 24?

1) n is a multiple of 4 2) n is a multiple of 6

i had the method of seing if the number in the question (24) has common prime factors with the multiples of n. in this case : 24= 2^3 * 3

4= 2*2 INSUFF 6= 3*2 SUFF BUT IN THIS CASE THIS METHOD HAS FAILED ME . OA= E

thank you!

Hello All,

Unfortunately I brought this question back from the dead (last update 2007!) because I am missing something fundamental here. I selected that both answer choices were sufficient because each answer choice provided a NO answer AND did not provide a YES answer.

1.) n is a multiple of 4 SUFFICIENT bc there are no 3s in the prime box 2.) n is a multiple of 6 SUFFICIENT bc there is not enough 2s in the prime box

Even if both are INSUFFICIENT, C would also work because we know that there are not enough factors in n's prime box... Is there an assumption I'm missing? Someone please, put me to shame!

Re: is the positive integer n a multiple of 24? [#permalink]
18 Feb 2013, 04:18

Expert's post

mejia401 wrote:

buffett76 wrote:

DOES SOMEONE HAVE A GENERAL PROCEDURE TO SOLVE THIS AWFUL QUESTIONS?

is the positive integer n a multiple of 24?

1) n is a multiple of 4 2) n is a multiple of 6

i had the method of seing if the number in the question (24) has common prime factors with the multiples of n. in this case : 24= 2^3 * 3

4= 2*2 INSUFF 6= 3*2 SUFF BUT IN THIS CASE THIS METHOD HAS FAILED ME . OA= E

thank you!

Hello All,

Unfortunately I brought this question back from the dead (last update 2007!) because I am missing something fundamental here. I selected that both answer choices were sufficient because each answer choice provided a NO answer AND did not provide a YES answer.

1.) n is a multiple of 4 SUFFICIENT bc there are no 3s in the prime box 2.) n is a multiple of 6 SUFFICIENT bc there is not enough 2s in the prime box

Even if both are INSUFFICIENT, C would also work because we know that there are not enough factors in n's prime box... Is there an assumption I'm missing? Someone please, put me to shame!

Is the positive integer n a multiple of 24?

(1) n is a multiple of 4. If n=4, then the answer is NO but if n=24, then the answer is YES. Not sufficient. (2) n is a multiple of 6. If n=6, then the answer is NO but if n=24, then the answer is YES.Not sufficient.

(1)+(2) n is a multiple of both 4 and 6 which means that it's a multiple of least common multiple of 4 and 6, which is 12. So, even taken together statements are not sufficient, since n can be for example 12 as well as 24. Not sufficient.

Answer: E.

Generally if a positive integer n is a multiple of positive integer a and positive integer b, then n is a multiple of LCM(a,b).

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