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Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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01 Nov 2014, 15:39

1

This post received KUDOS

Bunuel wrote:

TomB wrote:

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.

Hey Bunuel,

In the question, we are talking about integers so why are we not considering negative values. Wouldn't the statements be insufficient in that case. Can you please explain why negative integers are out of scope

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.

Hey Bunuel,

In the question, we are talking about integers so why are we not considering negative values. Wouldn't the statements be insufficient in that case. Can you please explain why negative integers are out of scope

Second statement says that y > x > 3, so both x and y are positive.

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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16 Aug 2016, 19:11

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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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20 Aug 2016, 03:51

Hi Bunuel,

From x > 3 the minimal value of x is 4, and the min value of y is 13 as per y> 3x=12, So the range should br 13-4=9 Can you please explain why the value of the range is 10 .

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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20 Aug 2016, 04:25

AbhijitGoswami wrote:

Hi Bunuel,

From x > 3 the minimal value of x is 4, and the min value of y is 13 as per y> 3x=12, So the range should br 13-4=9 Can you please explain why the value of the range is 10 .

Thanks

It should be 13-4 = 9 only.

It MUST be a typo from Bunuel side.
_________________

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