numlock31 wrote:

Is the sum of six consecutive integers even?

1. The first integer is odd

2. The average of six integers is odd

Can someone evaluate stment 2?

I get that stment two does not even make sense b/c if you take the avg of any 6 consec integers you will get a non-integer. I figured this by saying that the integers are x, x+1, x+2, x+3, x+4, x+5 and the avg is

(6x+15)/6

However someone said that stment 2 is suff b/c:

avg = (sum of the 6 intergers)/6. Thus if the avg is an odd number then

the sum must be even since an odd number * 6 is even. Thus we know sum is even and stment 2 is sufficient.

Did I do something wrong or is the answer to this Q really A.

This question must be wrong. Any six consecutive integers will always be an odd number because you have 3 odds and 3 evens no matter what. Since the question can be answered without ANY of the choices, the question must be wrong, The only way that this question would make sense is if the number of integers was odd, say 5.

_________________

Best,

AkamaiBrah

Former Senior Instructor, Manhattan GMAT and VeritasPrep

Vice President, Midtown NYC Investment Bank, Structured Finance IT

MFE, Haas School of Business, UC Berkeley, Class of 2005

MBA, Anderson School of Management, UCLA, Class of 1993