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Is there a better strategy for this problem

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Intern
Joined: 13 Jan 2007
Posts: 29
Location: India
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Is there a better strategy for this problem [#permalink]  11 Feb 2007, 23:26
Hi fellows,
I came across this problem, just wanted to know if there is a better way of solving this problem then the approach I had:

1. A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?
(A) 14
(B) 16
(C) 21
(D) 22
(E) 27
MyStrategy:
consider,
m = miles traveled per gallon AND g = no. of gallons
mg = 462 (I)
(m-6)g = 336 (II)

Solving eq I and and II
We get, (Solving I and II consumed lot of time)
m = 336 / 21
Now miles/ gallon in city is
336 / 21 â€“ 6 = 16
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 24 [0], given: 0

[#permalink]  12 Feb 2007, 00:07
I just do 462 - 336 = 21 for the size of the tank.
336/21 = 16

This is how I would do this problem, but I think it is good to get in the habit of setting up equations they way you did because most of the time that is what you have to do. I usually do not set up the equation so I struggle a bit with word translations.
Senior Manager
Joined: 04 Jan 2006
Posts: 280
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Kudos [?]: 20 [0], given: 0

Re: Is there a better strategy for this problem [#permalink]  12 Feb 2007, 01:24
auniyal wrote:
Hi fellows,
I came across this problem, just wanted to know if there is a better way of solving this problem then the approach I had:

1. A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?
(A) 14
(B) 16
(C) 21
(D) 22
(E) 27
MyStrategy:
consider,
m = miles traveled per gallon AND g = no. of gallons
mg = 462 (I)
(m-6)g = 336 (II)

Solving eq I and and II
We get, (Solving I and II consumed lot of time)
m = 336 / 21
Now miles/ gallon in city is
336 / 21 â€“ 6 = 16

Here is how I would set up the equation.

mpg(highway) - mpg(city) = 6

Assuming n = full tank gallon of this car

mpg(highway) = 462(mile) / n (gallon) = 462/n mpg
mpg(city) = 336 (mile) / n (gallon) = 336/n mpg

So,

(462/n) - (336/n) = 6

462 - 336 = 6n
n = 126/6 = 21 gallon

mpg(city) = 336/21 = 16 mpg.
Intern
Joined: 13 Jan 2007
Posts: 29
Location: India
Followers: 0

Kudos [?]: 2 [0], given: 0

[#permalink]  12 Feb 2007, 08:30
Thanks buddies for your replies
[#permalink] 12 Feb 2007, 08:30
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