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# Is there a specific technique to resolve such questions?

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Manager
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Is there a specific technique to resolve such questions?  [#permalink]

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16 Feb 2007, 16:35
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Is there a specific technique to resolve such questions?

Answer options A, B, C, D, E
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Manager
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17 Feb 2007, 12:10
Yes the answer is C. Do we simply need to calculate or is there a method to find it?
trivikram wrote:
Isnt this C?
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17 Feb 2007, 12:34
You can directly see that D 20,300/3,900~20/4=5
That eliminates A, because it's obvious that 142/16>5
B 48/8.8~48/9>45/9=5
It's easy to calculate 3.3*5=16.5, which means that 16.2/3.3~5

Also you can easily see that 13*5=65, 13*4= 52
So 51,400/13 < 4 => C
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17 Feb 2007, 13:00
Yes i follow that. So the approach is to make approximations and then eliminate. Thanks

jvujuc wrote:
You can directly see that D 20,300/3,900~20/4=5
That eliminates A, because it's obvious that 142/16>5
B 48/8.8~48/9>45/9=5
It's easy to calculate 3.3*5=16.5, which means that 16.2/3.3~5

Also you can easily see that 13*5=65, 13*4= 52
So 51,400/13 <4> C
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17 Feb 2007, 13:42
sgoll wrote:
Yes the answer is C. Do we simply need to calculate or is there a method to find it?
trivikram wrote:
Isnt this C?

you dont need to calculate unless the fractions are too close
17 Feb 2007, 13:42
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# Is there a specific technique to resolve such questions?

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