r019h wrote:

Is there a way to do this problem without splitting into two triangles?

A certain triangle has two angles measuring 45 and 75 degrees. the side opposite 45 deg has length 6. what is the length of the side opposite the 75 deg angle?

a. 2+3 SQRT3

b. 3(SQRT 3+1)

c. 6

d. 6 SQRT3

e. 2+6 SQRT2

I can elminate C, but Im not sure what to do after this. I split the the triangle into 2 and got an isosceles triangle (75,75,30) where two of the sides are 6... and another triangle (30,45,105).

I don't know what to do from here. plz help