Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Is there an alternate method to Anagrams? [#permalink]
19 Oct 2013, 19:09

Hi Folks, Appreciate help from members here to educate me on using Permutations/Combinations method instead of using ANAGRAMS.

For instance, the number of *distinct* ways you can arrange the word QUANTITATIVE using the anagram method looks like 12!/(2!*3!*2!), (basically 2!,3! and 2! in the denominators being repetitions of letters A,T and I). Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't.

So, I was wondering there should be a direct permutation/combination approach to solve word arrangement problems? Any insight will be greatly helpful.

Re: Is there an alternate method to Anagrams? [#permalink]
19 Oct 2013, 19:29

mniyer wrote:

Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't

Could you please give examples/instances for the same

Re: Is there an alternate method to Anagrams? [#permalink]
20 Oct 2013, 02:06

Sharvickr wrote:

mniyer wrote:

Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't

Could you please give examples/instances for the same

There can be many examples. Almost all the problems in MGMAT series feature the ANAGRAM approach. But in general, if we are asked to find the number of possible ways to distinctly arrange a word, say "QUANTITATIVE" how do we approach using a perm/comb idea? For the e.g. in question, a part of it sounds permutation (for QUNVE because order does matter) and the rest looks like permutation and combination (because order does not matter within AA, TT or II but it DOES when we do across A,T,I ).

Re: Is there an alternate method to Anagrams? [#permalink]
20 Oct 2013, 02:33

mniyer wrote:

Sharvickr wrote:

mniyer wrote:

Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't

Could you please give examples/instances for the same

There can be many examples. Almost all the problems in MGMAT series feature the ANAGRAM approach. But in general, if we are asked to find the number of possible ways to distinctly arrange a word, say "QUANTITATIVE" how do we approach using a perm/comb idea? For the e.g. in question, a part of it sounds permutation (for QUNVE because order does matter) and the rest looks like permutation and combination (because order does not matter within AA, TT or II but it DOES when we do across A,T,I ).

How do we put these pieces together?

You could think of it in the following way

First a basic example, "AB" can be arranged in 2! {"AB", "BA"} ways. But "AA" can be arranged only in one way For the word "QUANTITATIVE" group in the following manner (QUNVE AA II TTT) AA --> 2! (if letters are distinct) TTT --> 3! (if letters are distinct) II -->2! (if letters are distinct)

Since the above three groups have repetitions, out of 10! possible ways, the latter three groups have only one possible way of arrangement. Therefore, no of ways for "QUANTITATIVE" is 10!/(2!*2!*3!)

Re: Is there an alternate method to Anagrams? [#permalink]
20 Oct 2013, 03:24

1

This post received KUDOS

Expert's post

mniyer wrote:

Hi Folks, Appreciate help from members here to educate me on using Permutations/Combinations method instead of using ANAGRAMS.

For instance, the number of *distinct* ways you can arrange the word QUANTITATIVE using the anagram method looks like 12!/(2!*3!*2!), (basically 2!,3! and 2! in the denominators being repetitions of letters A,T and I). Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't.

So, I was wondering there should be a direct permutation/combination approach to solve word arrangement problems? Any insight will be greatly helpful.

Thanks!

THEORY:

Permutations of \(n\) things of which \(P_1\) are alike of one kind, \(P_2\) are alike of second kind, \(P_3\) are alike of third kind ... \(P_r\) are alike of \(r_{th}\) kind such that: \(P_1+P_2+P_3+..+P_r=n\) is:

\(\frac{n!}{P_1!*P_2!*P_3!*...*P_r!}\).

For example number of permutation of the letters of the word "gmatclub" is \(8!\) as there are 8 DISTINCT letters in this word.

Number of permutation of the letters of the word "google" is \(\frac{6!}{2!2!}\), as there are 6 letters out of which "g" and "o" are represented twice.

Number of permutation of 9 balls out of which 4 are red, 3 green and 2 blue, would be \(\frac{9!}{4!3!2!}\). _________________

Re: Is there an alternate method to Anagrams? [#permalink]
20 Oct 2013, 07:47

Bunuel wrote:

mniyer wrote:

Hi Folks, Appreciate help from members here to educate me on using Permutations/Combinations method instead of using ANAGRAMS.

For instance, the number of *distinct* ways you can arrange the word QUANTITATIVE using the anagram method looks like 12!/(2!*3!*2!), (basically 2!,3! and 2! in the denominators being repetitions of letters A,T and I). Though this method is straight forward, questions in GMAT doesn't make this very apparent. Instead we need to apply basic logic, arrive at the ANAGRAM word from question stem and THEN apply the above method. Sometimes I resolve the ANAGRAM word right and sometimes I don't.

So, I was wondering there should be a direct permutation/combination approach to solve word arrangement problems? Any insight will be greatly helpful.

Thanks!

THEORY:

Permutations of \(n\) things of which \(P_1\) are alike of one kind, \(P_2\) are alike of second kind, \(P_3\) are alike of third kind ... \(P_r\) are alike of \(r_{th}\) kind such that: \(P_1+P_2+P_3+..+P_r=n\) is:

\(\frac{n!}{P_1!*P_2!*P_3!*...*P_r!}\).

For example number of permutation of the letters of the word "gmatclub" is \(8!\) as there are 8 DISTINCT letters in this word.

Number of permutation of the letters of the word "google" is \(\frac{6!}{2!2!}\), as there are 6 letters out of which "g" and "o" are represented twice.

Number of permutation of 9 balls out of which 4 are red, 3 green and 2 blue, would be \(\frac{9!}{4!3!2!}\).

Great post! Thanks Bunuel!!

gmatclubot

Re: Is there an alternate method to Anagrams?
[#permalink]
20 Oct 2013, 07:47

Hey, Last week I started a few new things in my life. That includes shifting from daily targets to weekly targets, 45 minutes of exercise including 15 minutes of yoga, making...

This week went in reviewing all the topics that I have covered in my previous study session. I reviewed all the notes that I have made and started reviewing the Quant...

I started running as a cross country team member since highshcool and what’s really awesome about running is that...you never get bored of it! I participated in...