Find all School-related info fast with the new School-Specific MBA Forum

It is currently 26 Dec 2014, 02:47

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Senior Manager
Senior Manager
User avatar
Joined: 20 Dec 2004
Posts: 257
Followers: 6

Kudos [?]: 81 [0], given: 0

Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 [#permalink] New post 23 Mar 2008, 12:00
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is |x - 1| < 1 ?

1. (x - 1)^2 <= 1
2. x^2 - 1 > 0
_________________

Stay Hungry, Stay Foolish

Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3576
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 386

Kudos [?]: 1950 [0], given: 359

GMAT ToolKit User Premium Member
Re: DS [#permalink] New post 23 Mar 2008, 12:11
Expert's post
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Senior Manager
Senior Manager
User avatar
Joined: 20 Dec 2004
Posts: 257
Followers: 6

Kudos [?]: 81 [0], given: 0

Re: DS [#permalink] New post 23 Mar 2008, 12:20
walker wrote:
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.


I think I am loosing it ....

I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1

So why should it not be C ?
_________________

Stay Hungry, Stay Foolish

Senior Manager
Senior Manager
User avatar
Joined: 24 Feb 2008
Posts: 349
Schools: UCSD ($) , UCLA, USC ($), Stanford
Followers: 130

Kudos [?]: 1557 [0], given: 2

Re: DS [#permalink] New post 23 Mar 2008, 12:28
neelesh wrote:
walker wrote:
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.


I think I am loosing it ....

I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1

So why should it not be C ?


Combining 1 & 2 we get x e (1,2] but this is still not sufficient since the question is really asking is x e (0,2). Picking 1.5 for instance leads to a "yes", while picking 2 leads to a "no".
_________________

Chinese Democracy is misunderstood...at your nearest BestBuy.

Best AWA guide here: how-to-get-6-0-awa-my-guide-64327.html

Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3576
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 386

Kudos [?]: 1950 [0], given: 359

GMAT ToolKit User Premium Member
Re: DS [#permalink] New post 23 Mar 2008, 12:30
Expert's post
neelesh wrote:
So why should it not be C ?

Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes"
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3576
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 386

Kudos [?]: 1950 [0], given: 359

GMAT ToolKit User Premium Member
Re: DS [#permalink] New post 23 Mar 2008, 12:31
Expert's post
chineseburned, thanks. I did not see your post
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Senior Manager
Senior Manager
User avatar
Joined: 20 Dec 2004
Posts: 257
Followers: 6

Kudos [?]: 81 [0], given: 0

Re: DS [#permalink] New post 23 Mar 2008, 12:35
walker wrote:
neelesh wrote:
So why should it not be C ?

Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes"



Thanks walker and chineseburned..

I think I need to take a break ....what a silly a@# mistake..... :cry:.... :wall
_________________

Stay Hungry, Stay Foolish

Re: DS   [#permalink] 23 Mar 2008, 12:35
    Similar topics Author Replies Last post
Similar
Topics:
If x 0, is |x| <1? (1) x^2<1 (2) |x| < 1/2 banksy 3 26 Feb 2011, 15:23
Is |x-1|<1? a) (x-1)^2 <= 1 b) x^2-1>0 bigfernhead 4 28 Nov 2008, 13:03
Is |x-1|< 1 ? (1) (x-1)^2 <= 1 (2) x^2 - 1 > 0 jjhko 7 11 Sep 2008, 02:58
Is |x + 1| < 2 ? 1. (x - 1)^2 < 1 2. x^2 - 2 < 0 beckee529 13 28 Oct 2007, 19:30
Is |x-1| < 1 ? 1) (x-1)^2 <= 1 2) x^2 - 1 > 0 iced_tea 2 01 Oct 2006, 21:15
Display posts from previous: Sort by

Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.