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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1

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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 [#permalink] New post 23 Mar 2008, 13:00
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Is |x - 1| < 1 ?

1. (x - 1)^2 <= 1
2. x^2 - 1 > 0
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Re: DS [#permalink] New post 23 Mar 2008, 13:11
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.
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Re: DS [#permalink] New post 23 Mar 2008, 13:20
walker wrote:
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.


I think I am loosing it ....

I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1

So why should it not be C ?
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Re: DS [#permalink] New post 23 Mar 2008, 13:28
neelesh wrote:
walker wrote:
E

|x - 1| < 1 --> is x (0,2)

1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient
2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient
1&2 x e (1,2]. insufficient.


I think I am loosing it ....

I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1

So why should it not be C ?


Combining 1 & 2 we get x e (1,2] but this is still not sufficient since the question is really asking is x e (0,2). Picking 1.5 for instance leads to a "yes", while picking 2 leads to a "no".
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Re: DS [#permalink] New post 23 Mar 2008, 13:30
neelesh wrote:
So why should it not be C ?

Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes"
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Re: DS [#permalink] New post 23 Mar 2008, 13:31
chineseburned, thanks. I did not see your post
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Re: DS [#permalink] New post 23 Mar 2008, 13:35
walker wrote:
neelesh wrote:
So why should it not be C ?

Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes"



Thanks walker and chineseburned..

I think I need to take a break ....what a silly a@# mistake..... :cry:.... :wall
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Re: DS   [#permalink] 23 Mar 2008, 13:35
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