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Senior Manager
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 [#permalink]
23 Mar 2008, 13:00
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 > 0
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CEO
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E|x - 1| < 1 --> is x (0,2) 1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient 2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient 1&2 x e (1,2]. insufficient.
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Senior Manager
Joined: 20 Dec 2004
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walker wrote: E
|x - 1| < 1 --> is x (0,2)
1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient 2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient 1&2 x e (1,2]. insufficient. I think I am loosing it .... I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1 So why should it not be C ?
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Senior Manager
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neelesh wrote: walker wrote: E
|x - 1| < 1 --> is x (0,2)
1. (x - 1)^2 <= 1 --> x e [0,2]. insufficient 2. x^2 - 1 > 0 --> x e (-∞,1)&(1,+∞). insufficient 1&2 x e (1,2]. insufficient. I think I am loosing it .... I was able to get exactly where you finished but then I argued that using 1&2 we know that x e (1,2]....meaning |x-1| will never be less than 1. And hence we can answer the question stem as a yes or no.....That is |x-1| is actually > 1 So why should it not be C ? Combining 1 & 2 we get x e (1,2] but this is still not sufficient since the question is really asking is x e (0,2). Picking 1.5 for instance leads to a "yes", while picking 2 leads to a "no".
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CEO
Joined: 17 Nov 2007
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Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
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neelesh wrote: So why should it not be C ? Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes"
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CEO
Joined: 17 Nov 2007
Posts: 3593
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 230
Kudos [?]:
1298
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chineseburned, thanks. I did not see your post
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Senior Manager
Joined: 20 Dec 2004
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walker wrote: neelesh wrote: So why should it not be C ? Because x=2 and x=1.5 satisfy both conditions, but the answers are "no" and "yes" Thanks walker and chineseburned.. I think I need to take a break ....what a silly a@# mistake.....  ....
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